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Katarina [22]
3 years ago
13

HELP ASAP!!!! WILL GIVE BRAINLIEST! Tamara bought yarn for $39 and 2 pairs of knitting needles. Her total cost for the yarn and

knitting needles was $69. Tamara writes an equation that represents the cost of each pair of knitting needles. If k represents the cost of each pair of knitting needles, which statements about verifying the value of k are true?
CHECK ALL THAT APPLY


A.) Tamara should substitute k = 30 into the equation 39 + 2 k = 69.


B.) After she substitutes the correct value for k into the equation, Tamara should find that the left side of the equation is equal to the right side.


C.) Tamara should substitute k = 15 into the equation 39 + 2 k = 69.


D.) After she substitutes the correct value for k into the equation, Tamara should find that the left side of the equation is not equal to the right side.


E.) To verify the solution to the equation, Tamara multiplies the solution by 2 and then adds it to 39. Then, she checks that it is equal to 69.


F.) To verify the solution to the equation, Tamara adds the solution to 2 and then adds it to 69. Then, she checks that it is equal to 39.
Mathematics
2 answers:
Alona [7]3 years ago
6 0

Answer:

2,3,5

Step-by-step explanation:

amid [387]3 years ago
4 0

Answer:

B. C. E

Step-by-step explanation:

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The first thing to do in this case is to perform the division and then compare with the simplified expression to determine the values of a, b, c and d.
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3 years ago
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1/x - 1/(x+1) ≤ 0 Please help quickly
Ymorist [56]
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Therefore x(x+1)≤0, and if two numbers multiply to a negative number, one of them has to be negative and the other has to be positive. In this case, because x+1>x, x≤0, and x+1≥0

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3 years ago
Find constant of variation k if y varies directly as x, when y = 3 when x = 8. K =?
posledela

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Answer:

24\sqrt{2}

Step-by-step explanation:

We can measure the number of diagonals each path takes:

From point 1, the path travels 6 diagonals, ending up at point D.

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Since your question mentions each are 2 cm by 2 cm, this is equivalent to 2\sqrt{2}.

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