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Wittaler [7]
3 years ago
15

What is the factored form of x2 + 4xy − 21y2?

Mathematics
1 answer:
kow [346]3 years ago
8 0

Answer:

\mathrm{Factor}\:x^2+4xy-21y^2:\quad \left(x-3y\right)\left(x+7y\right)

Step-by-step explanation:

Given the expression

x^2+4xy-21y^2

We can write the expression by breaking it into the groups such as:

=\left(x^2-3xy\right)+\left(7xy-21y^2\right)

\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-3xy\mathrm{:\quad }x\left(x-3y\right)

\mathrm{Factor\:out\:}7y\mathrm{\:from\:}7xy-21y^2\mathrm{:\quad }7y\left(x-3y\right)

=x\left(x-3y\right)+7y\left(x-3y\right)

\mathrm{Factor\:out\:common\:term\:}x-3y

=\left(x-3y\right)\left(x+7y\right)

Therefore,

\mathrm{Factor}\:x^2+4xy-21y^2:\quad \left(x-3y\right)\left(x+7y\right)

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