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34kurt
3 years ago
13

Solve -9 2/7 -(10 3/7)

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
6 0
I hope this helps you. i converted the fractions before doing the arithmetic to make life easier.

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PLEASE ANYONE HELP !!!!
podryga [215]

Answer:

28 should do it

Step-by-step explanation:

35+35+82= 152


180-152=28

8 0
2 years ago
I need some help. Please
Ilya [14]

Are you able to ask your teacher?

7 0
3 years ago
Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. Thi
Dovator [93]

Complete question:

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.

A) Find the mean and standard deviation for the number of girls in groups of 36 births.

B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.

C) Is the result of 33 girls significantly high? A result of 33 girls would suggest the method is effective or is not effective?

Answer:

a) mean = 18

Standard deviation =3

b) low range = 12

High range = 24

c) The result of 33 girls is significantly high. Yes, the method is effective.

Step-by-step explanation:

Given:

p = 0.5

n = 36

a) The mean is the product of n and p

Mean u = np

u = 36 * 0.5 = 18

The standard deviation is the square root of the product of n and p&q.

S.d ó = \sqrt{npq}

= \sqrt{np(1-p)}

= \sqrt{36(0.5)(1-0.5)} = \sqrt{9} = 3

b) To find the range rule of thumb:

• For low range

Low range = u - 2ó

= 18 - (2 * 3)

= 12

• High range

= u + 2ó

= 18 + (2*3)

= 24

c) The result is significantly high, because 33 is greater than 24 girls.

A result of 33 girls would prove the method as effective.

8 0
3 years ago
Positive numbers are located to the right of zero on the number line.<br><br><br> True False
Trava [24]

\text {Hi!}

\text {The Answer to this Problem Is:}

\fbox {True!}

\text {When we look at a number line with positive and negative numbers we see} \text {that positives are to the right and negatives are to the left.}

\text {As you can see the number line on the image that all} \text {the negative numbers are to the left and positive numbers are to the right.}

\text {\underline {Remember}}

\text {Positive to the Right.}

\text {Negative to the Left.}

\text {Best of Luck!}

7 0
3 years ago
Read 2 more answers
What are the values of u and v
lubasha [3.4K]

Answer:

u=72

v=61

Step-by-step explanation:

for U:

54+54=108

180-108=72

For V:

180-58=122

122/2=61

5 0
3 years ago
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