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telo118 [61]
3 years ago
13

WHO KNOWS THIS? I NEED HELP PLS

Mathematics
2 answers:
VLD [36.1K]3 years ago
8 0

Answer:

Its D

Step-by-step explanation:

NeX [460]3 years ago
6 0

Answer:

sorry i do not know

Step-by-step explanation:

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ANSWER THIS FAST PLS NO PHOTOS THOSE BLOCKED
Alexxx [7]
The answer is approximately 8.1
4 0
2 years ago
Read 2 more answers
How many time 2/3 can go into 16<br><br> Explanation pls!!
tensa zangetsu [6.8K]

Answer:

24 times

Step-by-step explanation:

16 divided by 2/3 is 24

hope this helped!

7 0
1 year ago
Your co-worker, Amanda, and you are reliving your high school athletic "glory days" during a coffee break. She played basketball
topjm [15]

Answer:

Our score = 0.60, Amanda's score = 0.25

Step-by-step explanation:

For Amanda

μ = 15 , σ = 4

z- score for X = 16 is (From z table)

z = (X - μ)/σ = (16 - 15)/4 = 0.25

For us

μ = 310 , σ = 25

z score for X = 325 (From z table)

z = (325-310)/25 = 0.60

Since our z score is better than Amanda's z score, we can say we did better

4 0
3 years ago
The youth group is going on a trip to the State Fair trip cost 63 dollars included in that price is 13 dollars for a concert tic
Marina CMI [18]

Answer:

The cost of one pass is 25$

Step-by-step explanation:

Call the cost of one of the passes, P.   So we have

63 =  13 + 2P - subtract 13 from both sides

50 = 2P - divide both sides by 2

25 = P

So the cost of one pass = $25

4 0
1 year ago
The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt
Marizza181 [45]

Answer:

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

L=w+2

now, we can find area

A=L\times W

now, we can plug it

A=(w+2)\times w

A=w^2+2w

we are given area =6

so, we can set it equal

and then we can solve for w

w^2+2w=6

w^2+2w-6=0

we can use quadratic formula

ax^2+bx+c=0

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can compare and find a,b and c

a=1 , b=2 , c=-6

w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}

w=-1+\sqrt{7},\:w=-1-\sqrt{7}

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

7 0
3 years ago
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