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sukhopar [10]
3 years ago
5

Kiran is getting dinner for his drama club on the evening of their final rehearsal.

Mathematics
1 answer:
gladu [14]3 years ago
4 0
4.98 for the water and for the food it’s 52.9 dollars for 10 pounds.
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What is the product? Assume x greater-than-or-equal-to 0 (StartRoot 3 x EndRoot + StartRoot 5 EndRoot) (StartRoot 15 x EndRoot +
OlgaM077 [116]

Answer:

3\sqrt5 x+ \sqrt x (6 \sqrt{10} +5\sqrt{3}) +10 \sqrt6

Step-by-step explanation:

To find the product :

(\sqrt{3x} +\sqrt5)(\sqrt{15x} +2\sqrt{30})

\sqrt{3x}(\sqrt{15x} +2\sqrt{30}) +\sqrt5(\sqrt{15x} +2\sqrt{30})\\\Rightarrow \sqrt{3x}\times \sqrt{15x} +\sqrt{3x}\times 2\sqrt{30} +\sqrt5 \times \sqrt{15x} +\sqrt5\times 2\sqrt{30}\\\Rightarrow \sqrt{45} \times x + 2 \sqrt{90x} + \sqrt{75x} + 2 \sqrt{150}\\\Rightarrow \sqrt{5 \times 9} \times x + 2 \sqrt{9\times 10x} + \sqrt{25 \times 3x} + 2 \sqrt{25 \times 6}\\\Rightarrow 3\sqrt5 x+ 2 \times 3 \sqrt{10x} +5\sqrt{3x} +2 \times 5 \sqrt6\\\Rightarrow 3\sqrt5 x+ 6 \sqrt{10x} +5\sqrt{3x} +10 \sqrt6

\Rightarrow 3\sqrt5 x+ \sqrt x (6 \sqrt{10} +5\sqrt{3}) +10 \sqrt6

Some identities used:

1. (a+b)(c+d) = a (c+d) + b(c+d)

2. \sqrt9  =3

3. \sqrt{25}  =5

4. \sqrt x \times \sqrt x=x

5. \sqrt a \times \sqrt b = \sqrt{ab}

So, the solution is 3\sqrt5 x+ \sqrt x (6 \sqrt{10} +5\sqrt{3}) +10 \sqrt6

8 0
3 years ago
Read 2 more answers
What is the answer to 632/50 can someone help pls.
bixtya [17]
The answer is 12.64. I hope I helped. :) 
8 0
3 years ago
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4/7m = 2/7( 2m+1 )<br> What is M?<br> Check Solution
aev [14]
4/7m = 2/7(2m + 1)
4/7m = 4/7m + 2/7
4/7m - 4/7m = 2/7
0 = 2/7 (incorrect)

no solution
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3 years ago
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X^2-x-7=0 complete the square
lesya692 [45]
Hello there!
Use the formula ( \frac{b}{2} )^2 in order to created a new term. Solve for x by using this term to complete the square.
x= \frac{1}{2}±  \frac{ \sqrt{29} }{2}

Hope this helps! :)
~Zain
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3 years ago
What are the first three common multiples of 12 and 28
Oksana_A [137]

84, 168, 252

Hope this helped =)

3 0
3 years ago
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