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3 years ago

Kiran is getting dinner for his drama club on the evening of their final rehearsal.

Mathematics

1 answer:

gladu [14]3 years ago

4 0

4.98 for the water and for the food it’s 52.9 dollars for 10 pounds.

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What is the product? Assume x greater-than-or-equal-to 0 (StartRoot 3 x EndRoot + StartRoot 5 EndRoot) (StartRoot 15 x EndRoot +

OlgaM077 [116]

Answer:

$3\sqrt5 x+ \sqrt x (6 \sqrt{10} +5\sqrt{3}) +10 \sqrt6$

Step-by-step explanation:

To find the product :

$(\sqrt{3x} +\sqrt5)(\sqrt{15x} +2\sqrt{30})$

$\sqrt{3x}(\sqrt{15x} +2\sqrt{30}) +\sqrt5(\sqrt{15x} +2\sqrt{30})\\\Rightarrow \sqrt{3x}\times \sqrt{15x} +\sqrt{3x}\times 2\sqrt{30} +\sqrt5 \times \sqrt{15x} +\sqrt5\times 2\sqrt{30}\\\Rightarrow \sqrt{45} \times x + 2 \sqrt{90x} + \sqrt{75x} + 2 \sqrt{150}\\\Rightarrow \sqrt{5 \times 9} \times x + 2 \sqrt{9\times 10x} + \sqrt{25 \times 3x} + 2 \sqrt{25 \times 6}\\\Rightarrow 3\sqrt5 x+ 2 \times 3 \sqrt{10x} +5\sqrt{3x} +2 \times 5 \sqrt6\\\Rightarrow 3\sqrt5 x+ 6 \sqrt{10x} +5\sqrt{3x} +10 \sqrt6$

$\Rightarrow 3\sqrt5 x+ \sqrt x (6 \sqrt{10} +5\sqrt{3}) +10 \sqrt6$

Some identities used:

1. $(a+b)(c+d) = a (c+d) + b(c+d)$

2. $\sqrt9 =3$

3. $\sqrt{25} =5$

4. $\sqrt x \times \sqrt x=x$

5. $\sqrt a \times \sqrt b = \sqrt{ab}$

So, the solution is $3\sqrt5 x+ \sqrt x (6 \sqrt{10} +5\sqrt{3}) +10 \sqrt6$

8 0

3 years ago

Read 2 more answers

What is the answer to 632/50 can someone help pls.

bixtya [17]

The answer is 12.64. I hope I helped. :)

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3 years ago

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4/7m = 2/7( 2m+1 )<br> What is M?<br> Check Solution

aev [14]

4/7m = 2/7(2m + 1)
4/7m = 4/7m + 2/7
4/7m - 4/7m = 2/7
0 = 2/7 (incorrect)

no solution

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3 years ago

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X^2-x-7=0 complete the square

lesya692 [45]

Hello there!
Use the formula $( \frac{b}{2} )^2$ in order to created a new term. Solve for x by using this term to complete the square.
$x= \frac{1}{2}± \frac{ \sqrt{29} }{2}$

Hope this helps! :)
~Zain

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3 years ago

What are the first three common multiples of 12 and 28

Oksana_A [137]

84, 168, 252

Hope this helped =)

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3 years ago