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koban [17]
2 years ago
9

Which of the following is equivalent to the product below?

Mathematics
1 answer:
lilavasa [31]2 years ago
6 0

Answer:

square root 3 that is a the answer

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HELP PLEASEEE
djyliett [7]

Answer:

Exact circumference is 7\frac{49}{150}km

Approximate circumference is 7.33 km

Step-by-step explanation:

We are given;

  • The diameter of a circle as 2\frac{1}{3} km

We are required to determine the exact and approximate circumference of the circle.

  • We know that the circumference of the circle is given by;
  • Circumference = πD, where D is the diameter

Taking π as 3.14

Circumference=3.14 (2\frac{1}{3}km)

                          =7\frac{49}{150}km

The exact circumference of the circle is 7\frac{49}{150}km

7\frac{49}{150}km=7.327 km\\                            = 7.33 km (nearest hundredth)

Thus, the approximate circumference of the circle is 7.33 km

6 0
3 years ago
A circle with centre O has a radius of 6.2 cm.
Paul [167]

Answer:

it could either be 10.781 or 65.6, if not either of em then iam truly very sorry

Step-by-step explanation:

6 0
2 years ago
A coordinate plane from negative 8 to 8 along the x-axis and from negative 7 to 7 along the y-axis. Which steps should be used t
sdas [7]

Answer:

see the explanation

Step-by-step explanation:

we have

y-4=\frac{1}{3}(x+2)

This is the equation of a line in point slope form

where

the point is (-2,4)

the slope is m=1/3

Remember that the formula of slope is "rise over run", where the "rise" (means change in y, up or down) and the "run" (means change in x, left or right)

so

To graph the line

1. Plot the point (–2,4).

2. From that point, count left 3 units and down 1 unit and plot a second point.

3. Draw a line through the two points

3 0
3 years ago
Read 2 more answers
in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume
Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The m\angle CAB and m\angle CAD.

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

m(arcADC)=m(arcAD)+m(arcDC)

228^\circ=180^\circ+m(arcDC)

228^\circ-180^\circ+=m(arcDC)

48^\circ+=m(arcDC)

The measure inscribed angle is half of the corresponding subtended arc.

m\angle CAD=\dfrac{1}{2}\times m(arcDC)

m\angle CAD=\dfrac{1}{2}\times 48^\circ

m\angle CAD=24^\circ

AB is the tangent. So, m\angle BAD=90^\circ because radius is perpendicular on the tangent and the point of tangency.

m\angle BAD=m\angle CAB+m\angle CAD

90^\circ=m\angle CAB+24^\circ

90^\circ -24^\circ=m\angle CAB

66^\circ=m\angle CAB

Therefore, m\angle CAB=66^\circ and m\angle CAD=24^\circ.

4 0
2 years ago
-10 + 10у + -3y +7<br>does anyone know the answer plz??????<br>​
PilotLPTM [1.2K]

☁️ Answer ☁️

I got: 7y - 3

Hope it helps.

Have a nice day hyung!~  ̄▽ ̄❤️

8 0
3 years ago
Read 2 more answers
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