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user100 [1]
3 years ago
8

Lines A and B are parallel A 1,2,50°,4 B 5, 6 ,78 ,m 2 = [?]°​

Mathematics
1 answer:
AfilCa [17]3 years ago
8 0

2 = 50 degrees

...............................

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The park shown is in the shape of a square. Is the perimeter rational or irrational? Area = 24,200 yd 2
dangina [55]

Answer:

irrational

Step-by-step explanation:

A = s^2

s^2 = 24,200

s = \sqrt{24200}

s = \sqrt{242 \times 100}

s = \sqrt{100 \times 121 \times 2}

s = 10 \times 11\sqrt{2}

s = 110\sqrt{2}

P = 4s

P = 4 \times 100 \sqrt{2}

P = 440 \sqrt{2}

The perimeter is irrational.

3 0
3 years ago
Find the missing side<br> Please help thank you!!
Savatey [412]

Answer:

c= \sqrt{41}

Step-by-step explanation:

a^{2} +b^{2} =c^{2} \\4^{2} + 5^{2} = 16 + 25 = \sqrt{41} = c

8 0
2 years ago
Read 2 more answers
FIRST CORRECT ANSWER WILL GET BRAINLIEST
mezya [45]

Answer:

They are parallel.

Step-by-step explanation:

They have the same slope, 7, and different y-intercepts, 4, -1/4, so they are parallel.

5 0
2 years ago
X 6.4.5-T
butalik [34]

Same strategy as before: transform <em>X</em> ∼ Normal(76.0, 12.5) to <em>Z</em> ∼ Normal(0, 1) via

<em>Z</em> = (<em>X</em> - <em>µ</em>) / <em>σ</em>   ↔ <em>X</em> = <em>µ</em> + <em>σ</em> <em>Z</em>

where <em>µ</em> is the mean and <em>σ</em> is the standard deviation of <em>X</em>.

P(<em>X</em> < 79) = P((<em>X</em> - 76.0) / 12.5 < (79 - 76.0) / 12.5)

… = P(<em>Z</em> < 0.24)

… ≈ 0.5948

8 0
3 years ago
consider the line y= 2/3x-0. Find the equation of the line that is parallel to this line and passes through the point (8, 4).
tresset_1 [31]
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)

slope intercept form :
y=m+b

m=slope

If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.

Data:
(8,4)
m=2/3

y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3  (slope intercept form)

Answer: The equation of the line would be: y=2/3 x-4/3.


if we have the next slope "m",then the perendicular slope will be:
m´=-1/m

We have this equation: y=2/3 x+0; the slope is: m=2/3.

The perpendicular slope will be: m`=-1/(2/3)=-3/2

And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:

y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16

answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
3 0
3 years ago
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