Answer:
graph{y>2/3x-1 [-10, 10, -5, 5]}
Explanation:
First, graph a line with the equation y=23x−1. This equation is in the form y=mx+b. 23 is the slope and −1 is the y-intercept.
graph{2/3x-1 [-10, 10, -5, 5]}
However, we are graphing an inequality so we're gonna have to shade either the area above the line or below the line. First, let's look at the inequality symbols.
> Greater than
< Less than
≥ Greater than or equal to
≤ Less than or equal to
If the inequality includes equal to, then the line will be solid. If not, then the line will be dotted. Since the inequality y>23x−1 doesn't contain the equal to, the line will be dotted.
The direction of the inequality sign matters too. If it's greater than, then the top area will be shaded. If it's less than, then the bottom area will be shaded. Since the inequality y>23x−1 has greater than, the top area will be shaded.
graph{y>2/3x-1 [-10, 10, -5, 5]}
Answer & Step-by-step explanation:
The Segment Addition Postulate states that AB + BC = AC when C is between A and B.
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___________________________________________________</h2><h2><em>I AM ALWAYS HAPPY TO HELP :)</em></h2>
Answer:
6, 9
Step-by-step explanation:
y1-y2 over x1-x2
slope formula ^^
So for this, we will be using synthetic division. To set it up, have the equation so that the divisor is -10 (since that is the solution of k + 10 = 0) and the dividend are the coefficients. Our equation will look as such:
<em>(Note that synthetic division can only be used when the divisor is a 1st degree binomial)</em>
- -10 | 1 + 2 - 82 - 28
- ---------------------------
Now firstly, drop the 1:
- -10 | 1 + 2 - 82 - 28
- ↓
- -------------------------
- 1
Next, you are going to multiply -10 and 1, and then combine the product with 2.
- -10 | 1 + 2 - 82 - 28
- ↓ - 10
- -------------------------
- 1 - 8
Next, multiply -10 and -8, then combine the product with -82:
- -10 | 1 + 2 - 82 - 28
- ↓ -10 + 80
- -------------------------
- 1 - 8 - 2
Next, multiply -10 and -2, then combine the product with -28:
- -10 | 1 + 2 - 82 - 28
- ↓ -10 + 80 + 20
- -------------------------
- 1 - 8 - 2 - 8
Now, since we know that the degree of the dividend is 3, this means that the degree of the quotient is 2. Using this, the first 3 terms are k^2, k, and the constant, or in this case k² - 8k - 2. Now what about the last coefficient -8? Well this is our remainder, and will be written as -8/(k + 10).
<u>Putting it together, the quotient is
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