Answer:
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In 20 minutes, John can wrap 10 small boxes and Hank can wrap 12 small boxes. So, Hank can wrap more small boxes in 20 minutes than John can.
Step-by-step explanation:
Given,
John wraps;
2 small boxes = 4 minutes
1 small box = 
In 20 minutes,
20 minutes = 
20 minutes = 10 small boxes
Hank wraps;
3 small boxes = 5 minutes
1 small box =
In 20 minutes = 
In 20 minutes, John can wrap 10 small boxes and Hank can wrap 12 small boxes. So, Hank can wrap more small boxes in 20 minutes than John can.
Keywords: division, multiplication
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This can help you
a) since it is discrete we need to think about the sum thing
it it was continuous we would look at an integral thing
so I think if I remember correctly we need to find c such that
<span><span>∑<span>i=0</span>3</span>c(<span>x2</span>+4)=1
b) </span>
problem b is a similar setup
Answer: Look at the number of points where the graphs intersect each other...the points where the graphs of the functions cross each other are the solutions to the system.
Upon looking, you should see 4 points where the graphs intersect, so there are 4 solutions to the non-linear system of equations.
Step-by-step explanation:
Answer:
Roots are not real
Step-by-step explanation:
To prove : The roots of x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0 are real for all real values of k ?
Solution :
The roots are real when discriminant is greater than equal to zero.
i.e. b^2-4ac\geq 0b
2
−4ac≥0
The quadratic equation x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0
Here, a=1, b=1-k and c=k-3
Substitute the values,
We find the discriminant,
D=(1-k)^2-4(1)(k-3)D=(1−k)
2
−4(1)(k−3)
D=1+k^2-2k-4k+12D=1+k
2
−2k−4k+12
D=k^2-6k+13D=k
2
−6k+13
D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))
For roots to be real, D ≥ 0
But the roots are imaginary therefore the roots of the given equation are not real for any value of k.
