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Lana71 [14]
3 years ago
15

Do all graphs of proportional relationships include the point (0, 0)? Explain.

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0
No. For example, if I gave you the equation y= 3x+5, the y-intercept will be at (0,5), eliminating the (0,0).
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If cos 0=2/3, what are the values of sin 0 and tan 0?
morpeh [17]

Answer:

Below

Step-by-step explanation:

● cos O = 2/3

We khow that:

● cos^2(O) + sin^2(O) =1

So : sin^2 (O)= 1-cos^2(O)

● sin^2(O) = 1 -(2/3)^2 = 1-4/9 = 9/9-4/9 = 5/9

● sin O = √(5)/3 or sin O = -√(5)/3

So we deduce that tan O will have two values since we don't khow the size of O.

■■■■■■■■■■■■■■■■■■■■■■■■■

●Tan (O) = sin(O)/cos(O)

● tan (O) = (√(5)/3)÷(2/3) or tan(O) = (-√(5)/3)÷(2/3)

● tan (O) = √(5)/2 or tan(O) = -√(5)/2

4 0
3 years ago
Solve the equation -9v-9=-27 for v.
Nikolay [14]

Answer:

v=2

Step-by-step explanation:

-9v-9=-27

add nine to both sides

-9v-9+9=-27+9

simplify

-9v=-18

divide both sides by -9

-9v/-9   -18/-9

simplify y=2

hope this helps :) have a nice day !!

4 0
3 years ago
Read 2 more answers
The shapes below are mathematically similar​
s2008m [1.1K]

Answer:

5 cm is the answer brochacho

7 0
2 years ago
Write the equation in standard form. Identity the center and radius.<br> x² + y2 + 8x-4y-7=0
Masteriza [31]

Answer:

  • See below

Step-by-step explanation:

<u>Given equation:</u>

  • x² + y² + 8x - 4y - 7 = 0

<u>Convert this to standard form by completing the square:</u>

  • (x - h)² + (y - k)² = r², where (h, k) - center, r - radius
  • x² + 2*4x + 4² + y² - 2*2y + 2² - 16 - 4 - 7 = 0
  • (x + 4)² + (y - 2)² - 27 = 0
  • (x + 4)² + (y - 2)² = 27
  • (x + 4)² + (y - 2)² = (√27)²

The center is (- 4, 2) and the radius is √27

3 0
2 years ago
I’ll mark you as brainliest
Lapatulllka [165]

Step-by-step explanation:

1) -5n+10n

= 5n

2) -x-9+2x-10

= 2x-x-9-10

= x-19

3) -5(x-10)-x

= -5x+50-x

= -6x+50

4) 9-5(1-7x)

= 9-5+35x

= 35x+4

5) y^2-x

= 3^2-2

= 9-2

= 7

Do the remain questions by yourself, you can do it!

8 0
2 years ago
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