Answer:
The BOD5 for this sample is 5 mg/L
Explanation:
The BOD5 takes into consideration the difference between the initial DO and the final DO divided by the fraction of the sample tested in a 300 mL BOD flask. The problem states that the sample was directly placed in a BOD bottle so we assume that the volume used was 300 mL of the water sample. The fraction of water is 1 (300/300).
BOD5 = (10-5)/1
BOD 5 = 5 mg/L
Answer: at the equator the normal force will be 3.4N less and at the North Pole = 980N
Explanation:
So, we will start the Calculation by considering the equation below;
Fnet = F(g) - F(N); where Fnet = mv^2/ r.
Hence, F(g) - F(N) = mv^2/ r -------------(1).
Making F(N) the subject of the formula, we have;
F(N) = Gm1m2/r^2 - mv^2/r.
Thus, we have;
Gm1m2/r^2 = 6.68 × 10^-11 × (5.98 × 20^24) × 100/ 6.38 × 10^6 = 980N.
Also, we have;
mv^2/r = m4π^2r/T^2.
100 × 6.38 ×10^6 × 4π^2/(24 × 3600)^2 = 3.4N
Therefore, at the equator the normal force will be 3.4N less and at the North Pole = 980N.
History was a driving force behind such migration, since humans tended to move to new territory when they lacked food, shelter, or other resources--meaning that most of the conflicts throughout history have been driven by the same forces that drove migration out of Africa.
Answer:
East
Explanation:
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