Answer:
The explanation on how to do them is down below. If you have anymore questions pls feel free to ask
Step-by-step explanation:
So for number one you just need to state the sentence under the lines back wards but starting Lines m and n......
For number two name two angles that are inside the parallel lines and for three the opposite name two that are basically verticle outside of the parallel lines.
For number four they are across from each so they are verticle and since they are verticle they are concurrent so the m of 2 is 125.
In number 5,4 and 7 are corresponding so the are equal.
In number 6 the angles are alternate interior so they are congruent.
In number 7, the angles are corresponding so they are congruent.
In number 8, the angles are alternate exterior so they are congruent.
In number 9, the angles are are verticle so the are congruent.
In number 10, the answer is supplementary because on the top and bottom they add up to 180 degrees. And it part b 2 and 3 are adjacent and supplementary, so you subtract 119 from 180 and you get 61.
Answer:
92.5 cm²
Step-by-step explanation:
Lets take this step by step
Bottom rectangle is 2 by 5, so then 2*5 = 10
Large rectangle is 8 by 9, so 8*9 = 72
The triangle is 7 by 3, you get the 7 by subtracting the 5 side from the square because using the square you can tell that the height is 9 - something.
The 5 you get is from subtracting the cut part that you might have made because the height of that is 2, therefore you cut off 2 from 7 making it 5
Triangle area is h*b / 2, therefore 7*3 = 21/2 = 10.5
Add them all together, 10.5 + 10 + 72 and you get 92.5
Answer: The vertex is (-3, 2)
The equation y = -4(x + 3)^2 + 2 can be written as y = -4(x - (-3))^2 + 2
I rewrote x+3 as x - (-3)
Compare y = -4(x - (-3))^2 + 2 with the general template y = a(x-h)^2 + k
Note how
a = -4
h = -3
k = 2
So the vertex is (h,k) = (-3, 2)
Answer:
a. The possible dimensions of the total area are;
The width of the total area is (2·x + 8) inches
The length of the total area is (2·x + 10) inches
b. The dimensions of the photos are as follows;
The length of the photos are 10 inches
The width of the photos are 8 inches
Step-by-step explanation:
a. Given that the area, A = 4·x² + 36·x + 80
We get;
A = 4 × (x² + 9·x + 20) = 4 × (x + 4) × (x + 5) = (2·x + 8)·(2·x + 10)
Therefore, the possible dimensions of the total area (photo + mat) are;
The width of the total area (photo + mat) = (2·x + 8) in.
The length of the total area (photo + mat) = (2·x + 10) in.
b. The dimensions of the photos alone are shorter than the dimensions of the photo and mat combined by 2·x each
Therefore, we have the dimensions of the photos are as follows;
The length of the photo = (2·x + 10) in. - 2·x in. = 10 in.
The width of the photos = (2·x + 8) in. - 2·x in. = 8 in.
