Ask question

Ask question

All categories

3 years ago

10

During a basketball practice, Mai attempted 40 free throws and was successful on 25% of them. How many successful free throws di

d she make? If you get stuck, consider using the double number lines.

1 answer:

dlinn [17]3 years ago

5 0

Answer:

6

Step-by-step explanation:

You might be interested in

In triangle UVW, the measure of angle W=90°, the measure of angle U=15°, and VW=81 feet, Find the length of WU to the nearest te

Hatshy [7]

Answer:

302.3

Step-by-step explanation:

4 0

3 years ago

Write the rule for this pattern 1, 2, 4, 7, 11

rusak2 [61]

I'm not sure how to write the rule, but every time you add one more to the sum of the last two. First, you add 1, then 2, then 3. 1+1=2 2+2=4 4+3=7 7+4=11 and so on. I hope this helps!

7 0

3 years ago

I need to know how to solve this question please help!

lorasvet [3.4K]

Answer:

-3

Step-by-step explanation:

log7 (1/343)

log7(7^-3)

-3

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20-%2064%20%7D%20" id="TexFormula1" title=" \sqrt{ - 64 } " alt=" \sqrt{ - 64 }

Kipish [7]

What’s the other number?

3 0

4 years ago

Element X decays radioactively with a half-life of eight minutes. If there are 800 g of element X, how long, to the nearest 10th

Harman [31]

Answer: 41.5 min

Step-by-step explanation:

This problem can be solved with the Radioactive Half Life Formula:

$A=A_{o}.2^{\frac{-t}{h}}$ (1)

Where:

$A=22 g$ is the final amount of the radioactive element

$A_{o}=800 g$ is the initial amount of the radioactive element

$t$ is the time elapsed

$h=8 min$ is the half life of the radioactive element

So, we need to substitute the given values and find $t$ from (1):

$22 g=(800 g) 2^{\frac{-t}{8 min}}$ (2)

$\frac{22 g}{800 g}=2^{\frac{-t}{8 min}}$ (3)

$\frac{11}{400}=2^{\frac{-t}{8 min}}$ (4)

Applying natural logarithm in both sides:

$ln(\frac{11}{400})=ln(2^{\frac{-t}{8 min}})$ (5)

$-3.593=-\frac{t}{8 min}ln(2)$ (6)

Clearing $t$ :

$t=41.46 min \approx 41.5 min$ This is the time elapsed

7 0

3 years ago