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miss Akunina [59]

3 years ago

7

Libby needs to cut pieces of oak molding that are 3/4 yard long. She has 2 yards of oak molding. How many pieces can she cut? Ho

w much molding will be left over?

1 answer:

jek_recluse [69]3 years ago

3 0

Answer: She can make two 3/4 yards long of oak molding. She will have half of the second one left over.

Step-by-step explanation:

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3 years ago

Read 2 more answers

two sides of a triangle measures 25 cm + 35 CM which of the following would be the measure of the third side

Oxana [17]

Assuming those are the legs of the triangle and that you need to find the hypotenuse... I would use the formula: a^2+b^2=c^2
It doesn't matter what a and b are, just fill it in.
25^2+35^2=c^2
625+1225=c^2
1850=c^2
Take the square root of 1850, it isn't a perfect square so I got: 43.01.
If you want, just round it to 43, idc.
So, if I were to check my work, I would need to remember that the hypotenuse is the longest side.
Since 43 is the hypotenuse, it is the longest side.

5 0

4 years ago

The ratio of volume of a cone and a hemisphere of same base radius and height is?

aliya0001 [1]

Answer:

1/2

Step-by-step explanation:

Since it is given that the cone and the hemisphere have the same height, and since the height of a hemisphere would be equal to its radius, the cones height must also be equal to its base radius.

With this information we can use the respective volume formulas.

Hemisphere: $\frac{2}{3}$ πr^3

Cone: $\frac{1}{3}$ πhr^2

Since h (height) = r we can say the cone volume equals:

$\frac{1}{3}$ πr^3

Now to find the ratio we divide the cone volume equation by the hemisphere volume equation

pi and r^3 cancels out from the division and we are left with

ratio = (1/3)/(2/3)

ratio = 1/2

7 0

3 years ago

Suppose that the hourly wages of fast food workers are normally distributed with an unknown mean and standard deviation. The wag

Nutka1998 [239]

Answer: 1.303639

Step-by-step explanation:

The t-score for a level of confidence $(1-\alpha)$ is given by :_

$t_{(df,\alpha/2)}$ , where df is the degree of freedom and $\alpha$ is the significance level.

Given : Level of significance : $1-\alpha:0.80$

Then , significance level : $\alpha: 1-0.80=0.20$

Sample size : $n=40$

Then , the degree of freedom for t-distribution: $df=n-1=40-1=39$

Using the normal t-distribution table, we have

$t_{(df,\alpha/2)}=t_{39,0.10}=1.303639$

Thus, the t-score should be used to find the 80% confidence interval for the population mean =1.303639

8 0

3 years ago