Josh is solving the equation 2 % + 2% and predicts that his

Kelly works at her own nail

Sergeeva-Olga [200]

Answer:

(x×11)÷52.25

Step-by-step explanation:

if 11=52.25 and y=x then x11÷52.25 i think that is the answer

6 0

3 years ago

HELP PLEASE<3 Find the missing angle Btw its trigonometry

ira [324]

Answer:

x = 16.6

Step-by-step explanation:

Since we know the measure of an acute angle (31 degrees) of a right angle triangle, and of the side opposite to the angle (10), and we need to find the measure of the adjacent side "x", we use the tangent function:

$tan(\theta) = \frac{opposite}{adjacent} \\tan(31^o)=\frac{10}{x}\\x=\frac{10}{tan(31^o)} \\x \approx 16.64279$

which rounded to one decimal is

x = 16.6

6 0

3 years ago

How is 6/10 written as a decimal?

BARSIC [14]

It’s written as 0.6 in decimal form

6 0

3 years ago

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12 POINTS Simplify i38. i −1 −i 1

Karolina [17]

Are you sure you've copied down the original problem exactly as given? i38 = 38i can't be simplified. Perhaps you meant i^38, which is a different matter.

Note that i^38 = i^32 * I^4 * I^2.

Note that i^0, i^4, i^8, etc., all equal 1. Therefore,

i^38 = (1)(1)i^2 = 1*(-1) = -1 (answer)

3 0

3 years ago

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Suppose that in a random sample of 300 employed Americans, there are 57 individuals who say that they would fire their boss if t

otez555 [7]

Answer:

The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 300, \pi = \frac{57}{300} = 0.19$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.19 - 1.96\sqrt{\frac{0.19*0.81}{300}} = 0.1456$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.19 + 1.96\sqrt{\frac{0.19*0.81}{300}} = 0.2344$

The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.

4 0

3 years ago