Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
Answer:
The discrimant of this equation is 144.
Step-by-step explanation:
First you have to move all the variables to one side to make the equation/expression into 0 by substracting 8x² to both sides :
9x² + 14x + 13 = 8x²
9x² + 14x + 13 - 8x² = 8x² - 8x²
x² + 14x + 13 = 0
It is given that the formula of discriminant is, D = b² - 4ac where a&b&c represent the number of the equation, ax²+bx+c = 0 :
x² + 14x + 13 = 0
D = b² - 4ac
= 14² - 4(1)(13)
= 196 - 52
= 144
-6/5,-236/5 would be the minimum
A) To buy one box of the new cereal it will be y=8*1 so 8$. 12-8= 4. So the original brand is 4$ more.
B) 4*4=16$
Answer
school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in
terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters
Step-by-step explanation:
