Your answer is correct!! 2/3
Cos theta = 75/115
theta = cos^-1 (75/115)
theta = 49.2 degrees
Answer:
Probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.
Step-by-step explanation:
We are given that the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars. Also, incomes for the industry are distributed normally.
<em>Let X = incomes for the industry</em>
So, X ~ N(
)
Now, the z score probability distribution is given by;
Z =
~ N(0,1)
where,
= mean income of firms in the industry = 95 million dollars
= standard deviation = 5 million dollars
So, probability that a randomly selected firm will earn less than 100 million dollars is given by = P(X < 100 million dollars)
P(X < 100) = P(
<
) = P(Z < 1) = 0.8413 {using z table]
Therefore, probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.
Interval Notation of b > 13/9 is [13/9, infinity)
Answer:
2.2 hr
Step-by-step explanation:
Let t = time
95t = distance of westbound train
105t = distance of eastbound train
95t + 105t = 440
200t = 440
t = 2.2 hr.