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3 years ago

7

Exponential growth or exponential decay last question please help ?

1 answer:

maksim [4K]3 years ago

6 0

This is exponential growth because the peak starts at the negative side and it ends up at the positive side. Therefore, it is exponential growth.

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Show all work to identify the asymptotes and state the end behavior of the function f(x)=5x/x-25

Nina [5.8K]

Using the asymptote concept, it is found that:

The vertical asymptote is of x = 25.

The horizontal asymptote is of y = 5.

Considering the horizontal asymptote, it is found that the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.

<h3>What are the asymptotes of a function f(x)?</h3>

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

$f(x) = \frac{5x}{x - 25}$

Considering the denominator, the vertical asymptote is:

x - 25 = 0 -> x = 25.

The horizontal asymptote is found as follows:

$y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{5x}{x - 25} = \lim_{x \rightarrow \infty} \frac{5x}{x} = \lim_{x \rightarrow \infty} 5 = 5$

Hence the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.

More can be learned about asymptotes and end behavior at brainly.com/question/28037814

#SPJ1

6 0

1 year ago

The amount of chlorine in a swimming pool is proportional to the volume of water. The pool has 2.5 milligrams of chlorine per li

stira [4]

Answer:

There are <u>20,000 milligrams</u> chlorine in the pool.

Step-by-step explanation:

Given:

The chlorine per liter of water in the pool is 2.5 milligrams.

The volume of water in the swimming pool is 8000 gallons.

Now, to find the quantity of chlorine in the pool.

Let the quantity of chlorine be $x.$

The gallons of water in the swimming pool = 8000.

The milligrams of chlorine per liter of water in the pool = 2.5.

According to question, the amount of chlorine in the swimming pool is proportional to the volume of water.

So, 2.5 mg of chlorine is equivalent to 1 liter.

Thus, $x$ is equivalent to $8000.$

Now, to get the quantity of chlorine by using cross multiplication method:

$\frac{2.5}{1} =\frac{x}{8000}$

<em>By cross multiplying we get:</em>

$20000=x\\\\x=20,000\ mg.$

Therefore, there are 20,000 milligram chlorine in the pool.

6 0

3 years ago

Make a table of ordered pairs for the equation. y= 1 2 x−3<br><br> PLEASE HELP !!

Hunter-Best [27]

All you need to do is plug in some x values and find the correspoding y value
when x=0, y=-3
when x=1, y=9
when x=2, y=21
when x=-1, y=-15

6 0

3 years ago

Find the value of x in terms of a

Tatiana [17]

Answers:

a= 5x± $\sqrt{25x^{2} +24u^{2} \\$

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6

u=± $\sqrt{2a(3z-5x}$

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2

<h2>Brainliest please!!!! It took me a while to figure this out!</h2>

7 0

3 years ago

Question 10(Multiple Choice Worth 5 points)

MAVERICK [17]

So u have-27, positive 36

4 0

2 years ago