<span>The
range of a function is the set of all values
(outputs) assumed by the dependent variable. Thus, according to this statement we can affirm that the correct answer of this question is the equation given by:
So:
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Let's find the range of the other functions to contrast this conclusion:
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So as shown in the figure below the range of this function includes -4</span>
The vertex of a quadratic equation is the maximum or minimum point on the equation's parabola.
Answer:
[f(1) - f(3)] / [1–3]
Step-by-step explanation:
<u>Formula</u>
f(x) = 6(2.5)
<u>How to find</u>
The average rate of change over the interval [a,b], or the secant line between the points a and b on the function f(x), is [f(a) - f(b)]/[a-b]. So, substitute a for 1 and b for 3, and you get [f(1) - f(3)] / [1–3]. The quotient of that is your average rate of change.
X-axis = A (-7,-3) B (-7,-10) C (-1,-3) first they changed to the x-axis which is this. Just so you know on the x-axis the x-axis stay and the y-axis changed which is this.
When they reflect again on the y-axis the verter of A' is
A' (7, 3) = answer
On the y-axis the y- axis doesnt change but the x-axis changed.
Hope this help!
If you have e two linear functions and on a graph they are parallel that means they have the same slope with different y intercepts. If they are parallel and have the same y intercept then they would be the same graph. So no it’s not possible because there would not be two different graphs/functions; they would be exactly the same.