Answer:
9801
Step-by-step explanation:
you can solve by putting 99 over 99 and then multiplying
Answer:
you have to add the numbers . when ever there is a total that means to add
Step-by-step explanation:
13+14=27
Answer:
1. S(1) = 1; S(n) = S(n-1) +n^2
2. see attached
3. neither
Step-by-step explanation:
1. The first step shows 1 square, so the first part of the recursive definition is ...
S(1) = 1
Each successive step has n^2 squares added to the number in the previous step. So, that part of the recursive definition is ...
S(n) = S(n-1) +n^2
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2. See the attachment for a graph.
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3. The recursive relation for an arithmetic function is of the form ...
S(n) = S(n-1) +k . . . . . for k = some constant
The recursive relation for a geometric function is of the form ...
S(n) = k·S(n-1) . . . . . . for k = some constant
The above recursive relation is not in either of these forms, so it is neither geometric nor arithmetic.
The height of the cone would be 10 being that fact that if multiplied by 2 you get 20x 5 equals 100
Answer:
i)
ii)
And replacing we got:
![P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883](https://tex.z-dn.net/?f=%20P%28X%20%5Cgeq%203%29%20%3D%201-%20%5B0.00317%2B0.0211%2B0.0669%5D%3D%200.90883)
iii) 
Step-by-step explanation:
Let X the random variable of interest "number of inhabitants of a community favour a political party', on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Part i
We want this probability:
Part ii
We want this probability:
And we can use the complement rule and we have:

And if we find the individual probabilites we got:
And replacing we got:
![P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883](https://tex.z-dn.net/?f=%20P%28X%20%5Cgeq%203%29%20%3D%201-%20%5B0.00317%2B0.0211%2B0.0669%5D%3D%200.90883)
Part iii
We want this probability:

And replacing we got:
