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lina2011 [118]
2 years ago
9

If the length of a rectangle is 5 m more than its width find the values of length and width if the area of a rectangle is 500 m²

​
Mathematics
1 answer:
astra-53 [7]2 years ago
3 0

Answer:

Length of the rectangle  =25

width of the rectangle  = 20

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'x' be the width of the rectangle

Given that the length of a rectangle is 5 m more than its width

Given that Area of the rectangle = 500m²

length of a rectangle = x +5

width of a rectangle = x

<u><em>Step(ii):-</em></u>

Area of the rectangle = length × width

             500 = x ( x+5)

          x² + 5 x = 500

      ⇒  x² + 5 x - 500 =0

      ⇒  x² +25x - 20 x - 500 =0

    ⇒  x( x+25) -20(x+25) =0

  ⇒  (x-20)(x+25) =0

 ⇒  x =20 and x=-25

we can choose x =20

<u><em>Step(iii):-</em></u>

Length of the rectangle = x +5 = 20 +5 =25

width of the rectangle  = 20

<u><em>Final answer</em></u>:-

Length of the rectangle  =25

width of the rectangle  = 20

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Answer:

The probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.

Step-by-step explanation:

Denote the events as follows:

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<em>Y</em> = an elementary or secondary school teacher holds a second job

The information provided is:

P (X) = 0.66

P (Y) = 0.46

P (X ∩ Y) = 0.22

The addition rule of probability is:

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Use this formula to compute the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.46+0.66-0.22\\=0.90

Thus, the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.

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