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Vanyuwa [196]
4 years ago
9

If you leave the faucet on for one half of a day, how many gallons of water do you waste?

Mathematics
1 answer:
Naddik [55]4 years ago
8 0
Well, it depends on how many gallons/hour or gallons/min are running down the faucet
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Write an informal proof to show triangles ABC and DEF are similar. Please don’t answer if you don’t know!!
Mila [183]

Answer:

ΔABC ~ ΔDEF

Step-by-step explanation:

If the given triangles ΔABC and ΔDEF are similar,

Their corresponding sides will be proportional.

\frac{\text{AB}}{\text{DE}}=\frac{\text{BC}}{\text{EF}}=\frac{\text{AC}}{\text{DF}}

By substituting the measures of the given sides,

\frac{4}{2}=\frac{6}{3}=\frac{2}{1}

2 = 2 = 2

Since, corresponding sides of both the triangles are proportional, both the triangles will be similar.

ΔABC ~ ΔDEF

8 0
3 years ago
A soccer team won only 10 of their first 30 games. How many of their remaining 20 games will they have to win to have a .500 rec
jeka94

Answer: 5 games

Step-by-step explanation: A .500 record means that the soccer team won half of their games ( that's how I interpret it). Since they are going to play 30 games, they need to win half of 30 or 15 games to have that record. 15-10 = 5. So, they need to win 5 more games to have a .500 record.

8 0
2 years ago
Dillon has 4 blue marbles and 3 times as many red marbles.Max has 8 times as many red marbles as Dillon.How much red marbles do
SCORPION-xisa [38]
Dillion has 4 blue marbles and 12 red marbles

And max has 96 red marbles
5 0
3 years ago
Which steps could be used to solve this story problem?
Airida [17]
C. Multiply $ 5 by 3, multiply $ 3 by 4, then multiply $ 13 by 3....then add the      products together
8 0
4 years ago
8 ABC please trig assignment
Papessa [141]

Using equivalent angles, the solutions are given as follows:

a) x = \frac{15\pi}{23}.

b) x = \frac{9\pi}{62}, x = \frac{53\pi}{62}.

c) x = \frac{3\pi}{8}, \frac{11\pi}{8}

<h3>What are equivalent angles?</h3>

Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant.

For item a, we have to find the equivalent angle on the 2nd quadrant, where the sine is also positive.

Hence:

\pi - \frac{8\pi}{23} = \frac{23\pi}{23} - \frac{8\pi}{23} = \frac{15\pi}{23}

Hence x = \frac{15\pi}{23}.

For item b, if two angles are complementary, the sine of one is the cosine of the other.

Complementary angles add to 90º = 0.5pi, hence:

x + \frac{11\pi}{31} = \frac{\pi}{2}

x = \frac{31\pi}{62} - \frac{22\pi}{62}

x = \frac{9\pi}{62}

The equivalent angle on the second quadrant is:

\pi - \frac{9\pi}{62} = \frac{62\pi}{62} - \frac{9\pi}{62} = \frac{53\pi}{62}

Hence the solutions are:

x = \frac{9\pi}{62}, x = \frac{53\pi}{62}

For item c, the angles are also complementary, hence:

x + \frac{\pi}{8} = \frac{\pi}{2}

x = \frac{4\pi}{8} - \frac{\pi}{8}

x = \frac{3\pi}{8}

The tangent is also positive on the third quadrant, hence the equivalent angle is:

x = \pi + \frac{3\pi}{8} = \frac{8\pi}{8} + \frac{3\pi}{8} = \frac{11\pi}{8}

Hence the solutions are:

x = \frac{3\pi}{8}, \frac{11\pi}{8}

More can be learned about equivalent angles at brainly.com/question/28163477

#SPJ1

6 0
2 years ago
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