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erma4kov [3.2K]
3 years ago
9

Multiply 25 x 47 x 3

Mathematics
1 answer:
dmitriy555 [2]3 years ago
6 0
3525 is your answer please consider brainliest<3
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Find the value of x in the parallelogram
lord [1]

Answer:

72 = x

Step-by-step explanation

154 is one of the degrees for that angle. And I seen 82 for the other one.

All you have to do is subtract 154 and 82 and you get 72.

8 0
2 years ago
A. -5<br> B. 11<br> C. 38 - 8i<br> D. 3+ 8i
siniylev [52]

Answer:

D.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the image point of (1,-1)(1,−1) after a translation left 4 units and down 5 units?
DENIUS [597]

Answer:

The new point would be (-3,-6)

Step-by-step explanation:

To solve this it is nice to graph the first point at (1,-1). Then move the point left 4 units, making x -3. and then 5 units down, which would make y -6.

8 0
3 years ago
What is an exponent for 147
Yuri [45]
147 is not a prime number 147= 49 * 3
49 is divisable by 7: 49= 7 * 7
7 is not divisable by anything
5 0
3 years ago
The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the
erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes  is 0.4786.

Step-by-step explanation:

The random variable <em>X</em> is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, <em>β</em> = 19 minutes.

The random variable <em>X</em> follows an Exponential distribution with parameter \lambda=\frac{1}{\beta}=\frac{1}{19}.

The probability distribution function of <em>X</em> is:

f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...

Compute the value of the event (<em>X</em> > 14) as follows:

P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786

Thus, the probability that the wait time is greater than 14 minutes  is 0.4786.

7 0
2 years ago
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