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lorasvet [3.4K]
3 years ago
5

Find the error, Rashid and Tia solve the quadratic equation (2x2-8x +10=0) by completing the square. Who is correct? Explain you

r reasoning.
Rashid
2x^2−8x+10=0
2x^2−8x=−10
2x^x−8x+16=−10+16
(x−4)2=6
x−4=±6–√
x=4±6–√

Tia
2x^2−8x+10=0
x^2−4x=0−5
x^2−4x+4=−5+4
(x−2)2=−1
x−2=±i
x=2±i
Mathematics
1 answer:
podryga [215]3 years ago
8 0
To solve a quadratic equation using completing the square method,
STEP 1
Divide through by the coefitient of the squared term.

Looking at the solutions of Rashid and Tia, we notice that Rashid did not divide through by the coefficient of x^2.

Therefore, Rashids solution is wrong.

We solve the equation using completeing the square as follows:
2x^2-8x+10=0 \\  \\ x^2-4x=0-5=-5 \\  \\ x^2-4x+4=-5+4=-1 \\  \\ (x-2)^2=-1 \\  \\ x-2=\pm i \\  \\ x=2\pm i
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A piece of cardboard is 13 inches by 26 inches. A square is to be cut from each corner and the sides folded up to make an open-t
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Answer:

Hence the maximum possible volume will be the 778.53 c.c

Step-by-step explanation:

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Solution :

Consider a rectangle of 13 x 26 dimension with and side of square  at corner be x.

(Refer the attachment)

Now,

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V(x)=x^3-39x^2+338x\\

V'(x)=3x^2-78x+338

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Now ,Solve the Quadratic Equation to get x values,

3x^2-78x+338=0

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x=[78±Sqrt[(78)^2-4*338*3)]/2*3

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x=[78±55.027]/6

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So when x=22.17

6x-78=6*22.17-78

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When x=3.8288

6*3.8288-78

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V(x)=x^3-39x^2+338x

V(x)=3.8288^3-39*(3.82883)^2+338*3.8288

V(x)=56.13-571.73+1294.13

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3 years ago
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Hey help me with this question plzzzz
Wittaler [7]
<h3>Two Answers: choice C, choice D</h3>

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