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3 years ago

Can you help me with this question? You get 20 points if it is correct OLNY.

Mathematics

2 answers:

blsea [12.9K]3 years ago

8 0

1 mile=5280 feet, and 4 1/4 miles=4.25 miles, so:

1 mile:5280 ceei
4.25 miles:?
4.25×5280÷1=22440 feet. As a result, 4 1/4 miles equal 22440 feet. Hope it help!

insens350 [35]3 years ago

3 0

The answer is 22,440......4 miles is 21,120 feet....1/4 of a mile is 1,320 feet.... so when you add em up you get 22,440 feet

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The smallest number that has 3,7 and 11 as prime factors

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Answer:

231

Step-by-step explanation:

Since prime numbers are always relatively prime, we can just multiply them together. 3*7*11=21*11=231

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3 years ago

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9514 1404 393

Answer:

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Step-by-step explanation:

Solving for r when n=2, we have ...

$A=P(1+r)^2\\\\\dfrac{A}{P}=(1+r)^2\\\\\sqrt{\dfrac{A}{P}}=1+r\\\\\boxed{r=\sqrt{\dfrac{A}{P}}-1}$

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3 years ago

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Answer:

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Step-by-step explanation: Hope this helps you out!!

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2 years ago

Give 1 pair of Vertical and 1 pair of Supplementary angles

mojhsa [17]

Solution:

Vertical angles are a pair of opposite angles formed by intersecting lines. re vertical angles. Vertical angles are always congruent.

These two angles (140° and 40°) are Supplementary Angles because they add up to 180°:

Notice that together they make a straight angle.

Hence,

From the image

The following pairs form vertical angles

$\begin{gathered} \angle1=\angle3(vertical\text{ angles)} \\ \angle2=\angle4(vertical\text{ angles)} \\ \angle5=\angle7(vertical\text{ angles)} \\ \angle6=\angle6(vertical\text{ angles)} \end{gathered}$

Hence,

One pair of the vertical angles is ∠1 and ∠3

Part B:

Two angles are said to be supplementary when they ad together to give 180°

Hence,

From the image,

The following pairs are supplementary angles

$\begin{gathered} \angle5+\angle6=180^0(supplementary\text{ angles)} \\ \angle5+\angle8=180^0(supplementary\text{ angles)} \\ \angle7+\angle8=180^0(supplementary\text{ angles)} \\ \angle6+\angle7=180^0(supplementary\text{ angles)} \\ \angle1+\angle2=180^0(supplementary\text{ angles)} \\ \angle1+\angle4=180^0(supplementary\text{ angles)} \\ \angle2+\angle3=180^0(supplementary\text{ angles)} \\ \angle3+\angle4=180^0(supplementary\text{ angles)} \end{gathered}$

Hence,

One pair of supplementary angles is ∠5 and ∠6

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