Quadratic factored form
1 answer:
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The given point (-3/5 , y) lies in the third quadrant.
It is also given that the point lies on a unit circle.
For a point (x,y) lying on a unit circle a and y are defined as:
x = cos θ
y = sin θ
So, we can say for the point (-3/5 , y) the value -3/5 is equal to cos θ
sec θ is the reciprocal of cos θ.
So, sec θ = -5/3
Using Pythagorean identity we can first find sin θ.
Since the point lies in 3rd quadrant, both sin and cos will be negative.
So, now we can write:
Answers:
sec θ = -5/3
cot θ = 3/4
It is also given that the point lies on a unit circle.
For a point (x,y) lying on a unit circle a and y are defined as:
x = cos θ
y = sin θ
So, we can say for the point (-3/5 , y) the value -3/5 is equal to cos θ
sec θ is the reciprocal of cos θ.
So, sec θ = -5/3
Using Pythagorean identity we can first find sin θ.
Since the point lies in 3rd quadrant, both sin and cos will be negative.
So, now we can write:
Answers:
sec θ = -5/3
cot θ = 3/4
Answer:
A equação da reta é dada por:
Step-by-step explanation:
Equação de uma reta:
A equação de uma reta tem o seguinte formato:
Em que a é o coeficiente angular e b é o coeficiente linear.
Coeficiente angular:
Com posse de dois pontos, o coeficiente angular é dado pela mudança em y dividida pela mudança em x.
A(-1, -2) e B(5,2)
Mudança em y: 2 - (-2) = 2 + 2 = 4
Mudança em x: 5 - (-1) = 5 + 1 = 6
Coeficiente angular:
Então:
Coeficiente linear:
Substituindo um ponto na equação, encontra-se o coeficiente linear.
B(5,2)
Quando . Então:
Então:
Answer:
Area under the normal curve: 0.6915.
69.15% probability of putting less than 24 ounces in a cup.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
You have been asked to calculate the probability of putting less than 24 ounces in a cup.
pvalue of Z when X = 24. So
has a pvalue of 0.6915
Area under the normal curve: 0.6915.
69.15% probability of putting less than 24 ounces in a cup.