Let the fist integer be x, the second is x+20
the product of the numbers is:
x(x+20)
the sum of the numbers is:
x+x+20=2x+20
the sum of the above operations will give us:
2x+20+x^2+20x=95
x^2+22x+20=95
this can be written as quadratic to be:
x^2+22x-75=0
solving the above we get:
x=3 and x=-25
but since the integers should be positive, then x=3
the second number is x+20=3+20=23
hence the numbers are:
3 and 23
kjkk
Step-by-step explanation:
Jjo
Answer: i don't need the money but i can try to help you
Step-by-step explanation:
Answer:
Step-by-step explanation:
Sin(30) / X = Sin(45) / 12
use algebra to isolate X
1 / X = [ Sin(45) / 12 ] / Sin(30)
flip both sides
X = Sin(30) / [Sin(45) /12 ]
invert the denominator on the right side
X = Sin(30) * 12/ Sin(45)
Do you know what Sin(30) is off the top of your head?
and also Sin(45) ?
these are worth remembering... and you can b/c they are just
sin(0) = 0/2
sin(30) = 1 / 2
sin(45) =
/2
sin(60)=
/ 2
sin(90) =
/ 2 (aka 1)
note the numerators just counts up 0, 1, 2, 3, 4 :)
Cos works the same way but counts from 90° back to 0 but exactly like sin other wise, hence why Cos and Sin both =
/2 at 45 °
anyway
X = 1 / 2 * 12/
/2
X = 3
A=3
B= 2
:) nice , huh