Answer:
1) In the first step, we need to predict the possible alleles for the cross. The dominant allele will be written with a capital letter. The recessive allele will be written with a small letter. Hence, the allele for brown hair colour will be B and the allele for red hair colour will be b.
2) In the second step, we need to determine the genotype of the parents. The genotype of the homozygous dominant parent will be BB. The genotype of the heterozygous brown hair colour will be Bb.
3) The punnet square for cross between these parents can be shown as follows:
B b
B BB Bb
B BB Bb
4) In the fourth step, lets determine the phenotype of the children. The phenotype of all the offsprings born will be brown hair colour.
5) The genotype from the punnet square shows that there is a 50% chance that the offsprings will be heterozygous dominant (Bb) for brown hair colour and their will be a 50% chance that the child born will be homozygous dominant (BB).
Answer:
All of the above are true
Explanation:
Organisms possess two types of genome viz; prokaryotic genome and eukaryotic genome. The eukaryotic genome is possessed by cells with a well-defined nucleus, where their genetic material (DNA). The prokaryotic genome, on the other hand, lacks a membrane-bound nucleus. The major organization or content between these two genomes are:
- Prokaryotic genomes generally have less DNA and fewer genes than eukaryotic genomes.
- Prokaryotic genomes have fewer repeated sequences and noncoding, intragenic sequences than eukaryotic genomes.
- Most prokaryotic genomes are contained in one circular chromosome while most eukaryotic genomes are contained on several linear chromosomes.
- In general, eukaryotic genomes contain many introns, repeated sequences, and transposable elements.
Based on this, all of the above options are TRUE
Answer:
D. four haploid cells
Explanation:
When meiosis is complete,four haploid cells are formed from a single diploid cell. The four daughter cells produced that contains half the number of chromosome than that of their parent cell. Due to meiosis the number of chromosomes remain fixed in a species from generation to generation.
The process results in four daughter cells that are haploid, which means they contain half the number of chromosomes of the diploid parent cell. Meiosis has both similarities to and differences from mitosis, which is a cell division process in which a parent cell produces two identical daughter cells.
Answer:
50%
Explanation:
Hi there!
We are given the hair types of two cats
The first one has long hair, and it's heterozygous, meaning it has one dominant, and one recessive allele. We are given that it is a carrier of the short hair allele, meaning in its genotype, it has the short hair gene (that doesn't necessarily mean it's there in its phenotype). However, since it has long hair (genotype), that means that the long hair allele is dominant (the gene that will always show), and the short haired one is recessive (the gene that gets "covered up" by the dominant allele). Let's say the genotype of the long haired cat is Tt, where T is the long hair, and t is the short hair
The second cat has short hair, and as we have mentioned above, the allele for short hair is recessive, so the short haired cat has 2 copies of the short hair allele. Its genotype is tt
Please see below for the Punnett Square
Hope this helps! :)
Answer:
Arp2/3 and formins differ in their mechanisms of actin polymerization
Explanation:
The actin cytoskeleton plays key roles in diverse cellular processes including, among others, morphogenesis and endocytosis. The Arp2/3 complex and formin family proteins are two different types of actin-binding proteins capable of modulating the dynamics of actin filaments. The Arp2/3 complex is well known to have a key role in spine morphogenesis by promoting the branching of existing actin filaments. On the other hand, formin proteins induce the formation of plasma membrane protrusions by promoting the formation of unbranched filaments.
