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3 years ago

The principle P=6000 A=6810 T=3 years

Mathematics

2 answers:

Brums [2.3K]3 years ago

5 0

Answer:

incomplete question

Step-by-step explanation:

that is what is wrong with your question

Alex787 [66]3 years ago

3 0

Answer:

r = 4.3%

Step-by-step explanation:

6810= 6000(x)^3

6810/6000= (x)^3

x = 1.043114431

r = 043114431

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AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

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$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

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