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Kamila [148]
2 years ago
11

What is the third quartile of this data set?

Mathematics
1 answer:
Lena [83]2 years ago
8 0

Answer:

40 so C would be your answer.

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PLEASE HELP!!!! ill give 100 points!!<br> SHOW ALL WORK PLEASE AND THANK YOU
Marysya12 [62]

The area of a triangle is 1/2 x base x height

Area = 1/2 x 24 x 28 = 336 square inches.

Because the corners are rounded the are would actually be just under 336 but no radius was given to get the exact area.

5 0
3 years ago
Read 2 more answers
Find the domain: y= 6+9x 6− x−1
inna [77]

Answer:

Domain = {All real values of x EXCEPT x = -5 and x = 7}

Step-by-step explanation:

This is a rational function given as y=\frac{6+9x}{6-|x-1|}y=

6−∣x−1∣

6+9x

The domain is the set of all real value of x for which the function is defined.

For rational functions, we need to find which value of x makes the denominator equal to 0. We need to exclude those values from the domain.

Now

6 - |x-1| = 0

|x-1| = 6

x- 1 = 6

or

-(x-1) = 6

x = 6+1 = 7

and

-x+1=6

x = 1-6 = -5

So, the x values of -5 and 7 makes this function undefined. So the domain is the set of all real numbers except x = -5 and x = 7

3 0
3 years ago
Suppose you received a score of 95 out of 100 on exam 1 . The mean was 79 and the standard deviation was 8 . If your score on ex
Schach [20]

Answer:

You did the same on both exams.

Step-by-step explanation:

To compare both the scores, we need to compute the z scores of both the exams and then compare the values. The formula for z-score is:

<u>Z = (X - μ)/σ</u>

Where X = score obtained

           μ = mean score

           σ = standard deviation

For Exam 1:

Z = (95 - 79)/8

  = 16/8

<u>Z = 2</u>

For Exam 2:

Z = (90 - 60)/15

  = 30/15

<u>Z = 2</u>

<u>The z-scores for both the tests are same hence the third option is correct i.e. </u><u>you did the same on both exams.</u>

8 0
3 years ago
Is 1:2:3 equivalent to 2:4:6​
Finger [1]

Answer:

Yes it is.

Step-by-step explanation:

Just multiply everything by 2.

5 0
2 years ago
nikita ran a 5-kilometer race in 39 minutes (0.65 of an hour) without training beforehand. in the first part of the race, her av
Nataliya [291]
Total distance 5 km; at 5km / 0.65 h =

Second part distance: x; at 6 km/h, during t2

First part distance: 5 - x; at 8.75 km/h, during t1

V = d/t ⇒ t = d/V

t2 = x/6
t1=[5-x]/8.75

t2 + t1 = 0.65

x/6 + [5-x]/8.75 = 0.65

x/6 + 5/8.75 - x/8.75 = 13/20

 x/6 - x/8.75 = 13/20 - 5/8.75

x/6 - 4x/35 =13/20 - 20/35

35x - 24x = (35*6)(35*13 - 20*20)/(20*35)

11 x = 16.5
x = 16.5/11 = 1.5 km












5 0
3 years ago
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