Answer:
54.872
Step-by-step explanation:
volume of a cube = s³
where s = side length
side length given here is 3.8
so volume = 3.8³ = 54.872
Answer:
Yesenia has qty 1 of 10s and qty 7 of 1s
Misty has qty 6 of 10s and qty 8 of 1s
<u>Step-by-step explanation:</u>
Note that there are two different types of blocks: 1s and 10s. Let x represent the number of 10s and y represent the number of 1s.
<u>Value of the blocks </u> <u>Number of blocks</u>
Yesenia: 1x + 7y 8
Misty: <u> </u> <u> </u>
Total: 8x + 5y 22
Start with the number of blocks that Misty has: 22 - 8 = 14
Next, how many 1s can be added to Yesenia's to make 5? 15 - 7 = 8
How many blocks are left over from Misty's 14? 14 - 8 = 6
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Fill in the information:
<u>Value of the blocks </u> <u>Number of blocks</u>
Yesenia: 1x + 7y 8
Misty: <u> 6x + 8y </u> <u> 14 </u>
Total: 8x + 5y 22
Answer:
(C) 10 units
Step-by-step explanation:
It is given that EFGH is a rhombus and EG = 16 and FH = 12.
We know that the diagonals of the rhombus are the perpendicular bisectors, therefore OF=6, OH=6, OE=8 and OG=8.
Now, using the Pythagoras theorem in ΔOFG, we have
Thus, the value of the side of the rhombus will be 10 units.
Hence, option C is correct.
