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MatroZZZ [7]
3 years ago
15

What is the constant of proportionality in the equation StartFraction x over y EndFraction StartFraction 2 over 9 EndFraction?

Mathematics
1 answer:
ziro4ka [17]3 years ago
4 0

Given:

The equation is:

\dfrac{x}{y}=\dfrac{2}{9}

To find:

The constant of proportionality.

Solution:

If y is directly proportional to x, then

y\propto x

y=kx                        ...(i)

Where, k is the constant of proportionality.

We have,

\dfrac{x}{y}=\dfrac{2}{9}

On cross multiplication, we get

9x=2y

Divide both sides by 2.

\dfrac{9}{2}x=y

Interchange the sides.

y=\dfrac{9}{2}x                ...(ii)

On comparing (i) and (ii), we get

k=\dfrac{9}{2}

The constant of proportionality is \dfrac{9}{2}. Therefore, the correct option is B.

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Answer:

(7,\frac{13}{3})

Step-by-step explanation:

we have

<em>The equation of the first line</em>

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<em>The equation of the second line</em>

y=\frac{4}{3}x-5 ------> equation B

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(-4)y=(-4)(\frac{1}{3}x+2)

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Adds equation B and equation C

y=\frac{4}{3}x-5\\-4y=-\frac{4}{3}x-8\\--------\\y-4y=-5-8\\-3y=-13\\y=\frac{13}{3}

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Answer:

f(x) has a limited range

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Step-by-step explanation:

Given the function;

f(x) = x^2+2

The domain is the value of the input variables for which the function will exist. According to the expression given, the function exists on all real values of x. The same goes with range which deals with the output values. It also exists on all real values from 2 and above.

Hence f(x) have a limited range (since values less than 2 are not included compare to domain that exists on all real values) and does not have a restricted domain.

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For the y intercept, y intercept occur at x = 0

substitute x = 0 into the function and get y

if y = f(x)

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f(x) is at maximum if d(fx))/dx = 0

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since  d(fx))/dx  = 0

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y = 0^2+2

y = 2

Hence f(x) has a maximum at the point (0, 2)

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