An even function can be reflected about the y axis and map onto itself
example: y=x^2
an odd function can be reflected about the origin and map onto itself
example: y=x^3
a simple test is the following
if f(x) is even then f(-x)=f(x)
if f(x) is odd then f(-x)=-f(x)
so
even function
subsitute -x for each and see if we get the same function
remember to fully expand these
g(x)=(x-1)^2+1=x^2-2x+1+1=x^2-2x+2 is the original one
g(x)=(x-1)^2+1
g(-x)=(-x-1)^2+1
g(-x)=(1)(x+1)^2+1
g(-x)=x^2+2x+1+1
g(-x)=x^2+2x+2
not same because the original has -2x
not even
g(x)=2x^2+1
g(-x)=2(-x)^2+1
g(-x)=2x^2+1
same, it's even
g(x)=4x+2
g(-x)=4(-x)+2
g(-x)=-4x+2
not the same, not even
g(x)=2x
g(-x)=2(-x)
g(-x)=-2x
not same, not even
g(x)=2x²+1 is the even function
Answer:
θ = 83°
Step-by-step explanation:
For acute angles, the sine of an angle is the cosine of its complement, and vice versa.
__
sin(θ) = cos(90° -θ) . . . . relation between sine and cosine
sin(θ) = cos(7°) . . . . . . . . given
90° -θ = 7° . . . . . . . . . matching arguments of cos( )
θ = 83° . . . . . . . . . add θ -7° to both sides
Answer:
The answer is 6!!!
Step-by-step explanation:
Answer:

Step-by-step explanation:
Using the distance formula, we see that the distance between (-4,4) and (-7,3) is
.
\left[x \right] = \left[ \frac{3}{8}\right][x]=[83] totally answer