In many cases the Law of Sines works perfectly well and returns the correct missing values in a non-right triangle. However, in
some cases the Law of Sines returns two possible measurements.
Consider the diagram below, and assume that m∠B=61∘, ¯¯¯¯¯¯¯¯AB=4.27 cm, and ¯¯¯¯¯¯¯¯AC=3.98 cm.
Using the Law of Sines, determine the value of m∠C. You should notice that there are actually two possible values - list both of them (separated by a comma).
m∠C= °
If we assume the diagram is to scale, which value of m∠C makes more sense? Enter the appropriate value.
m∠C= °
Using your answer to part (b), determine the length of BC.
¯¯¯¯¯¯¯¯BC= cm
Consider the diagram below, and assume that m∠B=61∘, ¯¯¯¯¯¯¯¯AB=4.27 cm, and ¯¯¯¯¯¯¯¯AC=3.98 cm.
Using the Law of Sines, determine the value of m∠C. You should notice that there are actually two possible values - list both of them (separated by a comma).
m∠C= °
If we assume the diagram is to scale, which value of m∠C makes more sense? Enter the appropriate value.
m∠C= °
Using your answer to part (b), determine the length of BC.
¯¯¯¯¯¯¯¯BC= cm
1 answer:
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Answer:
30/552
Step-by-step explanation:
In order to solve this problem you need to multiply the probability of getting grape for the first gumball with the probability of getting grape for the second gumball. Since there are 6 grape gumballs and a total of 24 gumballs (6*4). Then the probability of getting grape for the firs one is
Now there are only 5 grape gumballs available and one less in the total supply, therefore the probability of getting grape in the second try is
Finally we multiply them together to find the probability of getting two grapes in a row.
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