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3 years ago

A line with a slope of 2 passes through the points (0,4) and (-6,v). What is the value of v?

1 answer:

4 0

To solve this problem, we should create an equation using the given information. To do this, we should calculate the slope between the two points as if they were regular points, giving us:

change in y/change in x = (v-4)/(-6-0) = (v-4)/(-6)

Since we know that the slope is 2, we can set our calculated value for the slope of the line for the equation (v-4)/(-6) equal to 2, as shown below:

(v-4)/(-6) = 2

To solve this equation, we should multiply both sides of the equation by -6 to get rid of the denominator on the left side of the equation.

v-4 = -12

Next, we should add 4 to both sides of the equation to get the variable v alone on the left side of the equation, as shown below:

v = -8

Therefore, v =-8 is your answer.

Hope this helps!

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What is the value of x?

Nikolay [14]

Answer:

5 units (you are right!)

Step-by-step explanation:

The triangles ABD and BCD are similar.

Therefore,

$\frac{x}{10}=\frac{10}{4x} \\4x^{2}=100\\x^{2}=25\\x=5$

I hope this helped!

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3 years ago

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Norma-Jean [14]

Answer: (C)

Step-by-step explanation:

Looking at the diagram the area occurring continuously over a period of time is the constant point which ranges from -4 to -2 making the answer C

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3 years ago

Read 2 more answers

Find the first four terms of the recursive sequence defined by the following formula: an = an-1 4 where a4 = 2 1 4 , , , 2 1 4.

Elina [12.6K]

The first four-term of the sequence is found by the given equation $a_{n-1} = 4a_n$ is given as 144, 36, 9, and 9/4.

<h3>What is a sequence?</h3>

A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.

The given equation will be

$\rm a_n = \dfrac{a_{n-1}}{4} \\\\a_{n-1} = 4a_n$

And

$a_4 = 2 \dfrac{1}{4} = \dfrac{9}{4}$

For n = 4, we have

$\rm a_{4-1} = 4a_4\\\\a_3 \ \ \ = 4*\dfrac{9}{4} \\\\ a_3 \ \ \ = 9$

For n = 3, we have

$\rm a_{3-1} = 4a_3\\\\a_2 \ \ \ = 4*9 \\\\ a_2 \ \ \ = 36$

For n = 2, we have

$\rm a_{2-1} = 4a_2\\\\a_1 \ \ \ = 4*36 \\\\ a_1 \ \ \ = 144$

More about the sequence link is given below.

brainly.com/question/21961097

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2 years ago

In circle P with mNRQ = 60°, find the angle measure of minor arc NQ

Galina-37 [17]

Given:

m∠NRQ = 60°

To find:

The angle measure of minor arc NQ

Solution:

The inscribed angle is half of the intercepted arc.

$$\Rightarrow m\angle NRQ =\frac{1}{2} m(ar NQ)$

Multiply by 2 on both sides.

$$\Rightarrow 2 \times m\angle NRQ =2 \times \frac{1}{2} m(ar NQ)$

$$\Rightarrow 2 \ m\angle NRQ =m(ar NQ)$

Substitute m∠NRQ = 60°.

$$\Rightarrow 2\times 60^\circ=m(ar NQ)$

$$\Rightarrow 120^\circ=m(ar NQ)$

The measure of minor arc NQ is 120°.

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3 years ago

Plz help i am clueless

Ymorist [56]

Answer:

-3 and 3 for your start on your y axis and it goes up 2 and right one

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3 years ago