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allsm [11]
3 years ago
11

A young sumo wrestler goes on a special diet to gain weight. The variable w models the wrestlers weight in km after the wrestler

has been on a special diet for t months.
w=80+5.4t
How much weight does the wrestler gain every 2 months​
Mathematics
1 answer:
svetlana [45]3 years ago
5 0

Answer:

10.8kg

Step-by-step explanation:

Before he was on the diet he already weighed 80 kilograms, so it is not important to determining how much weight we gains in two months.  Instead we need to focus on the 5.4t part of the equation.  t represents the number of months so we need to substitute 2 for t and you get

5.4t

5.4(2)

10.8kg

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a bicycle has a listed price of 749.95 before tax. if the sales tax rate is 9.5%, find the total cost of the bicye with sales ta
Lemur [1.5K]

Answer:

  821.20

Step-by-step explanation:

The tax is added to the listed price in order to find the total cost. The tax is computed by multiplying the listed price by the tax rate.

  tax = 749.95 × 0.095 = 71.25 . . . . . (rounded up from 74.24525)

  total cost = listed price + tax = 749.95 +71.25 = 821.20

The total cost of the bicycle with sales tax included is 821.20.

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
Cos(theta) = - 3/4 and is in the 3rd quadrant, find the following:
elena-14-01-66 [18.8K]

Answer:

\begin{gathered} sin(\theta)=\frac{-\sqrt{7}}{4} \\ cos(\theta)=-\frac{3}{4} \\ tan(\theta)=\frac{\sqrt{7}}{3} \\ csc(\theta)=-\frac{4}{\sqrt{7}} \\ sec(\theta)=-\frac{4}{3} \\ cot(\theta)=\frac{3}{\sqrt{7}} \end{gathered}

Step-by-step explanation:

If theta is in the third quadrant, draw the diagram to easily identify the other trigonometric relations:

Solve for the missing leg of the triangle, using the Pythagorean theorem:

\begin{gathered} \text{ adjacent}^2+\text{ opposite}^2=\text{ hypotenuse}^2 \\ -3^2+\text{ opposite}^2=4^2 \\ \text{ opposite=}\sqrt{16-9} \\ \text{ opposite=}\sqrt{7} \end{gathered}

Therefore, for the trigonometric relationships:

\begin{gathered} \text{ sin\lparen}\theta)=\frac{opposite}{hypotenuse} \\ \text{ cos\lparen}\theta)=\frac{adjacent}{hypotenuse} \\ tan(\theta)=\frac{opposite}{adjacent} \\ csc(\theta)=\frac{hypotenuse}{opposite} \\ sec(\theta)=\frac{hypotenuse}{adjacent} \\ cot(\theta)=\frac{adjacent}{opposite} \end{gathered}

Now, substitute and solve for the relations:

\begin{gathered} sin(\theta)=\frac{-\sqrt{7}}{4} \\ cos(\theta)=-\frac{3}{4} \\ tan(\theta)=\frac{\sqrt{7}}{3} \\ csc(\theta)=-\frac{4}{\sqrt{7}} \\ sec(\theta)=-\frac{4}{3} \\ cot(\theta)=\frac{3}{\sqrt{7}} \end{gathered}

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1 year ago
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