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Sunny_sXe [5.5K]

3 years ago

6

Please help. 10 points

1 answer:

mestny [16]3 years ago

5 0

It's either A or C but correct me if I'm wrong :)

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given y>0 and dy/dx=(3x^2+4x)/yif the point (1,√10) is on the graph relating x and y, then what is y when x=0

jonny [76]

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3x^2+4x}y\iff y\,\mathrm dy=(3x^2+4x)\,\mathrm dx$
$\implies\displaystyle\int y\,\mathrm dy=\int(3x^2+4x)\,\mathrm dx$
$\implies \dfrac12y^2=x^3+2x^2+C$

When $x=1$ you have $y=\sqrt{10}$ , so

$\dfrac12(\sqrt{10})^2=1^3+2(1)^2+C\implies 5=1+2+C\implies C=2$

and so the particular solution to the ODE is

$\dfrac12y^2=x^3+2x^2+2$

Then when $x=0$ , you get

$\dfrac12y^2=0^3+2(0)^2+2=2$
$\implies y^2=4$
$\implies y=2$

where we omitted the negative root because it's given that $y>0$ .

4 0

3 years ago

An older person is 8 years older than seven times the age of a younger person. The sum of their ages is 32. What are their ages?

tatiyna

Answer:

there ages are 29 and 3 years old

3 0

2 years ago

Helpppppppp me plzzzzzzzzz

MAXImum [283]

Hi there’s some math apps for this

3 0

2 years ago

Read 2 more answers

How do i solve this equation

Gre4nikov [31]

X < -16 is the solution
Hope this helped

6 0

3 years ago

If 3x - 2y = 9 , 27x³- 8y³= 1377 , prove that xy = 4 <br><br><br><br>plzz answer this question...

solniwko [45]

Step-by-step explanation:

Here we are given that , the Value of

$3x - 2y = 9$
$27x^3 - 8y^3 = 1377$

And we need to find the prove that ,

$xy = 4$

We know a identity as ,

$(a-b)^3 = a^3-b^3-3ab(a-b)$

On cubing both sides of the given equation,

$(3x-2y)^3 = 9^3$

Simplify and then substitute ,

$27x^3-8y^3 -3(3x)(2y)(3x-2y ) = 729$

$1377 - 18xy (9) = 729$

$162xy = 1377-729$

$xy =\dfrac{648}{162}$

$xy = 4$

Hence Proved !

8 0

2 years ago