Answer:
X = 32
Y = 51
Step-by-step explanation:
It is give that triangle MNP is CONGRUENT to triangle TUS .
So, MN = TU , NP = US , MP = TS , Angle M = Angle T , Angle S = Angle P .
Angle S + Angle T + Angle U = 180 - ( Angle sum property of Triangle )
24 + 142 + ( 2x - 50) = 180
= 166 + ( 2x - 50) = 180
= 2x - 50 = 180 - 166
= 2x = 14 + 50
= x = 64/2
= x = 32
Side NP = Side SU
( 2x - y ) = 13
= 2*32 - y = 13 By putting x = 32
= 64 - y = 13
= - y = 13 - 64
= - y = - 51
= y = 51
If any doubt so please ask .
THANK YOU
A descending order polynomial is one with a reducing power of x.
The polynomial equation in descending order is:
![x^{12}+3x^7+4x^3-9x](https://tex.z-dn.net/?f=x%5E%7B12%7D%2B3x%5E7%2B4x%5E3-9x)
Hence, the correct option is Option D
Hey there!
When we subtract a negative, we're doing the same as adding because you're taking away negatives, and you're doing the opposite of subtracting- adding/
Therefore, we have:
-5 + 8
Now, we can think of a number line.
If we have -5 and go 8 to the right because we're adding and getting closer to 0, we'd actually get positive 3 because you'd be going past 0 and into the positives.
Therefore, the answer is positive :)
Hope this helps!
The answer to the problem- 1.5
Answer: The answer is ![\cos(x+y)=\cos x\cos y-\sin x\sin y.](https://tex.z-dn.net/?f=%5Ccos%28x%2By%29%3D%5Ccos%20x%5Ccos%20y-%5Csin%20x%5Csin%20y.)
Step-by-step explanation: We are to find the sum or the difference that could be used to prove the following identity:
![\cos(\pi+q)=-\cos q.](https://tex.z-dn.net/?f=%5Ccos%28%5Cpi%2Bq%29%3D-%5Ccos%20q.)
To prove the above identity, the following sum which results in a difference, will be appropriate
![\cos(x+y)=\cos x\cos y-\sin x\sin y.](https://tex.z-dn.net/?f=%5Ccos%28x%2By%29%3D%5Ccos%20x%5Ccos%20y-%5Csin%20x%5Csin%20y.)
The proof is as follows
![L.H.S.\\\\=\cos(\pi+q)\\\\=\cos \pi\cos q-\sin \pi\sin q\\\\=(-1)\cos q-0\times \sin q\\\\=-\cos q\\\\=R.H.S.](https://tex.z-dn.net/?f=L.H.S.%5C%5C%5C%5C%3D%5Ccos%28%5Cpi%2Bq%29%5C%5C%5C%5C%3D%5Ccos%20%5Cpi%5Ccos%20q-%5Csin%20%5Cpi%5Csin%20q%5C%5C%5C%5C%3D%28-1%29%5Ccos%20q-0%5Ctimes%20%5Csin%20q%5C%5C%5C%5C%3D-%5Ccos%20q%5C%5C%5C%5C%3DR.H.S.)
Thus, the answer is ![\cos(x+y)=\cos x\cos y-\sin x\sin y.](https://tex.z-dn.net/?f=%5Ccos%28x%2By%29%3D%5Ccos%20x%5Ccos%20y-%5Csin%20x%5Csin%20y.)