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3 years ago

PLEASE HELP DUE IN 1 HOUR IT WILL GIVE YOU 36 POINTS

Mathematics

2 answers:

PtichkaEL [24]3 years ago

8 0

Hmmm interesting.. but yeah the guy above me is correct.

DochEvi [55]3 years ago

6 0

I got this, I hope it solves your question

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What is the slop of y=-7

AlladinOne [14]

Answer:

slope of y = -7 is 0

Step-by-step explanation:

y = any number forms a graph of a horizontal line

x = any number forms a graph of a vertical line

For any horizontal line , the slope is always 0

for any vertical line , the graph is always undefined

So for y =-7 we will get a horizontal line at -7 on t

the slope of horizontal line y=-7 is 0

3 0

3 years ago

Please help! I really need help please I will give Brainliest!

Ostrovityanka [42]

Answer:

A) 4x+12y

B) 2(2x+6y) is one way to do it

Step-by-step explanation:

1+1+2 is 4 and 12y cannot be added to anything.

2 x 2 is 2 ans 6 x 2 is 12

4 0

3 years ago

The temperature in degrees Fahrenheit was recorded every two hours starting at midnight on the first day of summer. The data is

serg [7]

I’m pretty sure it’s line graph, if not that, bar graph
Hope this helps :D

6 0

3 years ago

SOMEONE PLEASE HELP MEEEEE3

Darina [25.2K]

The answer is (3,4)

3 0

3 years ago

Explain why the formula is not valid for matrices. Illustrate your argument with examples. (A + B)(A − B) = A2 − B2 The formula

julsineya [31]

Answer:

The formula is not valid because the commutative property with respect to the matrix product operation is not fulfilled in the vector space of the real matrices.

Step-by-step explanation:

The formula is not valid because the commutative property with respect to the matrix product operation is not fulfilled in the vector space of the real matrices. That is, AB does not necessarily equal BA.

$(A+B)(A-B) = A^2-AB+BA-B^2\neq A^2 - B^2$

$A=\left[\begin{array}{ccc}1&0&0\\0&0&6\\0&8&0\end{array}\right] \\B=\left[\begin{array}{ccc}0&2&0\\6&0&0\\0&0&9\end{array}\right] \\(A -B) = \left[\begin{array}{ccc}1&-2&0\\-6&0&6\\0&8&-9\end{array}\right]\\\\(A + B) = \left[\begin{array}{ccc}1&2&0\\6&0&6\\0&8&9\end{array}\right]\\(A - B)(A + B) = \left[\begin{array}{ccc}-11&2&-12\\-6&36&54\\48&-72&-33\end{array}\right]\\A^2 - B^2 = \left[\begin{array}{ccc}-11&0&0\\0&36&0\\0&0&-33\end{array}\right]\\$

7 0

3 years ago