Hi.
I believe the formula for R when you have the voltage and current is:
V/I = R
Plugging in the numbers:
220/4 = 55
The answer is the second option, 55.
Answer:
180 or b
Step-by-step explanation:
3 times 60 is 180 because there are 60 seconds in a minute
We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then,
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.
On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
9514 1404 393
Answer:
(x, y) ≈ (1.1642, 3.3930) and (3.4358, -0.39297)
Step-by-step explanation:
Solve the first equation for y, then substitute into the second.
5x +4/y = 7
4/y = 7 -5x
4/(7 -5x) = y
Then the second equation becomes ...
4x +x/(4/(7 -5x)) = 5
4x +x(7 -5x)/4 = 5
16x +7x -5x^2 = 20 . . . . . multiply by 4
5x^2 -23x +20 = 0 . . . . . put in standard form
We can use the quadratic formula to solve this.
x = (23±√((-23)² -4(5)(20)))/(2(5)) = (23±√129)/10
x = 2.3 ±√1.29 ≈ {1.1642, 3.4358}
y = 4/(7 -5x) = {3.3930, -0.39297}
Solutions are (x, y) ≈ (1.1642, 3.3930) and (3.4358, -0.39297).
V=<span>πr^2 h/3
V=</span><span>π(3)^2 (4)/3
V=37.7 yd^3 or 36 yd^3</span>
