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uranmaximum [27]
3 years ago
9

Suppose the trinomial x2 + 4x + 3

Mathematics
2 answers:
Zanzabum3 years ago
7 0

Answer:

bob

Step-by-step explanation:

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░░░▌░▄▄▄▐▌▀▀▀░░ This is Bob

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▀█▌░░░▄░▀█▀░▀ ░░ Copy And Paste Him onto all of ur brainly answers

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prisoha [69]3 years ago
4 0

Answer:

What???

La verdad no entiendo la pregunta pero va a ver alguien que si xd

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Solve and check the answers in the original equation
Scrat [10]
 12 + 5k + 15                     -24
------------------- =  -----------------------
      k + 3                      k - 4
 5k + 27              -24
------------ =  ---------------
  k + 3                k - 4

 (k - 4)(5k + 27) = -24 (k + 3)
5k^2 - 20k + 27k -108 = - 24k - 72
5k^2 + 31k - 36 = 0
(5k + 36)(k - 1) = 0

5k + 36 = 0; k = -36/5 = -7.2
k - 1 = 0; k = 1

solutions
k = 1 and k = -7.2

3 0
4 years ago
Suppose set A is the set of all U.S. states and set B is the set of all U.S. cities which are state capitals. Now, suppose the r
yarga [219]

Answer:

A

Step-by-step explanation:

ghfgkjhydrk;l'klhh

8 0
3 years ago
Factor 30-6v-18w30−6v−18w30, minus, 6, v, minus, 18, w to identify the equivalent expressions.
kompoz [17]

Answer:

Option C.

Step-by-step explanation:

The given expression is

30-6v-18w

We need to find the expression which is equivalent to the given expression.

The given expression can be rewritten as

6\times 5-6\times v-6\times 3w

The greatest common factor (G.C.F.) is 6. Taking out G.C.F., we get

30-6v-18w=6(5-v-3w)

Hence, the correct option is C.

7 0
4 years ago
What volume of this pyramid with Height 8ft and Width 6Ft on one side and 6ft on the other side.
Fiesta28 [93]
\bf \textit{volume of a square pyramid}\\\\
V=\cfrac{1}{3}Bh\qquad 
\begin{cases}
B=base=width\cdot length\\\\
h=height\\
----------\\
width=6\\
length=6\\
h=8
\end{cases}
7 0
3 years ago
Suppose a punter kicks a football so that the upward component of its velocity is 80 feet per second. If the ball is 3 feet off
Alexxandr [17]
So hmm check the picture below

\bf \qquad \textit{initial velocity}\\\\ h = -16t^2+v_ot+h_o \qquad \text{in feet}\\
\\
v_o=\textit{initial velocity of the object}\\
h_o=\textit{initial height of the object}\\
h=\textit{height of the object at "t" seconds}\\\\
-----------------------------\\\\
h(t)=3+80t-16t^2\iff h(t)=-16t^2+80t+3

a)

well, clearly is 80 ft/s

b)

when t = 1? well 80(1)

c)

in the picture, x-axis is the time and y-axis is the height
so, it reaches its maximum at the vertex, after "x" seconds

\bf \begin{array}{lcccll}
h(t)=&-16t^2&+80t&+3\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)

so it reached the vertex after \bf -\cfrac{{{ b}}}{2{{ a}}}\quad seconds

d)

the maximum height of the ball is \bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\quad feet

8 0
3 years ago
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