Please help with this anyone

What is the some of the finite arithmetic series?

garik1379 [7]

Answer:

455

Step-by-step explanation:

7 0

2 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

so

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

so

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

Let I (x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet,"

FrozenT [24]

Answer:

Step-by-step explanation:

L(x) means that Student X has an internet connection

C(x,y) means that students X and Y have chatted over the internet

The domain for variables X and Y comprise all students in your class. We now use quantifiers or algebraic functions to express each of the statements:

(A) Jerry does not have an internet connection

L(x) = 0

Where X represents Jerry

(B) Rachel has not chatted over the internet with Chelsea

C(x,y) = 0

Where X and Y represent Rachel and Chelsea

(C) Jan and Sharon have never chatted over the internet

L(x) + L(y) = 0

Where X and Y represent Jan and Sharon. If they have NEVER chatted over (the question didn't say they have never "with each other", it says they have never chatted at all) the internet, then they've probably never had an internet connection!

(D) No one in the class has chatted with Bob

Let Y represent Bob and X1, X2, ..., Xn represent everyone else in the class.

The value of Y is not significant here (because it is raised to the power of zero and that makes it equal to 1 and when 1 is multiplied by any X value, the X value or student remains the same) but we have to put it, to represent Bob.

The quantifier here is C (X1Y°, X2Y°, X3Y°, ..., XnY°)

5 0

3 years ago

HELP!!THANKS FOR ACCURACY

anyanavicka [17]

$\bf tan^2(x)-1=0\implies tan^2(x)=1\implies tan(x)=\pm\sqrt{1} \\\\\\ tan^{-1}[tan(x)]=tan^{-1}(\pm 1)\implies x=tan^{-1}(\pm 1)\implies x= \begin{cases} \frac{\pi }{4}\\\\ \frac{3\pi }{4}\\\\ \frac{5\pi }{4}\\\\ \frac{7\pi }{4} \end{cases}$

5 0

3 years ago

A new microwave that normally sells for $897.00 is on sale for 15% off. If the sales tax is 7.5%, then how much will you pay in

fiasKO [112]

Answer: $829.725

Step-by-step explanation:

5 0

2 years ago