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Mathematics

1 answer:

anyanavicka [17]3 years ago

5 0

$\bf tan^2(x)-1=0\implies tan^2(x)=1\implies tan(x)=\pm\sqrt{1} \\\\\\ tan^{-1}[tan(x)]=tan^{-1}(\pm 1)\implies x=tan^{-1}(\pm 1)\implies x= \begin{cases} \frac{\pi }{4}\\\\ \frac{3\pi }{4}\\\\ \frac{5\pi }{4}\\\\ \frac{7\pi }{4} \end{cases}$

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alina1380 [7]

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3 years ago

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UNO [17]

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Step-by-step explanation:

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Lana71 [14]

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