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2 years ago

Percent error between 20 and 16

Mathematics

1 answer:

Anna35 [415]2 years ago

8 0

Answer:

25%

Step-by-step explanation:

$\frac{(20-16)}{|16|}$ |×100

$\frac{4}{16}$ ×100

=0.25×100

=25%

=25%error

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Answer this question to chick you knowledge

NemiM [27]

Answer:

8.5 Yards

Step-by-step explanation:

Pythagorean Theorem: $c = \sqrt{a^{2} +b^{2} }$

a = 6

b = 6

Therefore: $c = \sqrt{6^{2} +6^{2} }$ = 8.485

The path is 8.5 yards long

4 0

3 years ago

A number is greater than 8. The same number is less than 10. The inequalities x > 8 and x < 10 represent the situation.

Semenov [28]

Answer:

There are infinite solutions because there is always another number between any two numbers.

Step-by-step explanation:

Pick any number (including decimal) add an extra decimal after the smallest one and then you have a number between them. E.g.

1.234 and 2.987

1.2341, 1.2342, 1.2343, ... are all between them

7 0

3 years ago

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Please help me with this D:

I am Lyosha [343]

Yes, because $120 - 36 = (120\times 36) - 4236 = 84$

Hope that helped :D

8 0

2 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

3 years ago

A circle has a radius of 2 feet. Which is the circumference of the circle?

stich3 [128]

Answer:

4pi

Step-by-step explanation:

Circle circumference = 2*pi*r

2*pi*2

4*pi

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2 years ago

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