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Jobisdone [24]
3 years ago
10

PLEASE HURRY Which of the following is NOT a solution in the solution region.

Mathematics
1 answer:
vovikov84 [41]3 years ago
5 0

Answer:

Need full problem.

Step-by-step explanation:

Need full problem.

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Can I have help with 42?
Sphinxa [80]
#42.
14n - 32 = 22
add 32 to both sides
14n - 32 + 32 = 22 + 32
simplify
14n = 54
divide both sides by 14
14n/14 = 54/14
simplify
n = 3 12/14
n = 3 6/7 or n = 3.857


8 0
3 years ago
Read 2 more answers
How do you solve a scale factor?
const2013 [10]
Basically you multiply the original length by the scale factor. So let's say there's a side length of 10 and the scale factor is .5, then you multiply 10 by .5 and get 5, that's all scale factor is . It can get larger/smaller, just depends on the number.
6 0
3 years ago
HI I really need help with this its in the picture
Hitman42 [59]
<h3>Answer:  24a^4 + 36a^3 + 12a^2</h3>

Explanation:

The blue rectangle has area of 4a^2*6a^2 = 24a^4

The red rectangle has area 4a^2*9a = 36a^3

The green rectangle has area 4a^2*3 = 12a^2

The total area is 24a^4 + 36a^3 + 12a^2

7 0
2 years ago
Find the missing side of the angle.<br> Need help, thank you!!
Alex787 [66]

Answer:

sqrt239

Step-by-step explanation:

Using the pythagoream thereom, we know that a^2+b^2=c^2.

so x^2+17=256

That makes x the square root of 239.

4 0
2 years ago
The X- and y-coordinates of point P are each to be chosen at random from the set of integers 1 through 10.
bagirrra123 [75]

Answer:

Ok, as i understand it:

for a point P = (x, y)

The values of x and y can be randomly chosen from the set {1, 2, ..., 10}

We want to find the probability that the point P lies on the second quadrant:

First, what type of points are located in the second quadrant?

We should have a value negative for x, and positive for y.

But in our set;  {1, 2, ..., 10}, we have only positive values.

So x can not be negative, this means that the point can never be on the second quadrant.

So the probability is 0.

3 0
3 years ago
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