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2 years ago

Which point is located at (2, -5)?

Mathematics

1 answer:

Yuki888 [10]2 years ago

3 0

Answer:

Step-by-step explanation:

Go to the right 2 units from the origin (0,0) and then down 5 units

The point at that location is J

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I just wanted to see if this was 8 or negative 8 :)

nirvana33 [79]

Answer:

It's a positive 8.

Step-by-step explanation:

You can't have a negative amount of money.

4 0

2 years ago

Combine like terms 18x-(-7x)+31-(-37)-5x

viktelen [127]

Answer:

20x+68

Step-by-step explanation:

6 0

2 years ago

A young sumo wrestler goes on a special diet to gain weight.

Ilia_Sergeevich [38]

Answer:

10.8 kg

Step-by-step explanation:

w = 80 + 5.4t

At time 0, when he starts the diet, his initial weight is

w = 80 + 5.4(0)

w = 80

80 kg.

After 2 months, t = 2. His weight is

w = 80 + 5.4t

w = 80 + 5.4(2)

w = 80 + 10.8

w = 90.8

90.8 kg.

His gain in 2 months was 90.8 kg - 80 kg = 10.8 kg

Answer: 10.8 kg

8 0

2 years ago

Read 2 more answers

Designer Dolls found that its number of Dress-Up Dolls sold, N, varies directly with their advertising budget, A, and inversely

Radda [10]

Answer:

25,600

Step-by-step explanation:

You can use the rule of three considering that the number of dolls sold varies directly with the advertising budget:

$54,000 → 9,600

$144,000 → x

$x=\frac{144,000*9,600}{54,000}$

x=25,600

According to this, the number of dolls sold if the amount of advertising budget is increased to $144,000 is 25,600.

4 0

3 years ago

Solve by taking the square root I need help understanding steps this is hard for me.

Shalnov [3]

Answer:

x= $-2 \pm \sqrt{13}$

Step-by-step explanation:

Given: $3x^{2} -12x+27= 0$

This is a quadratic equation.

$3x^{2} -12x+27= 0$

Taking common 3 from the equation given

⇒ $3(x^{2} -4x+9)=0$

dividing both side by 3

⇒ $x^{2} -4x+9=0$

By using different factor, we can observe this trinomial can not be factored.

∴ solving it by completing the square.

⇒ $x^{2} -4x+9=0$

adding 9 on both side

⇒ $x^{2} -4x= 9$

To get a perfect square number as coeffecient of x is 4, lets add both side by 4.

⇒ $x^{2} -4x+4= 13$

we know, $(x+2)^{2} = x^{2} +2\times x\times 2+2^{2}$

∴ $(x+2)^{2} =13$

Taking Square root on both side, remember; √a²= a

⇒ $(x+2)= \sqrt{13}$

opening parenthesis

⇒ $x+2= \sqrt{13}$

subtracting both side by 2

∴ x= $-2 \pm \sqrt{13}$

7 0

2 years ago