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Karolina [17]
3 years ago
7

Adam works at a bakery. He uses 1/8 of his flour supply to make bread and 3/4 of his flour supply to make other baked goods. If

Adam used 21 pounds of flour, how much flour did he have in this supply?
A. 22 pounds
B. 24 pounds
C. 34 pounds
D. 63 pounds
Mathematics
1 answer:
kykrilka [37]3 years ago
7 0

Answer: B  

he has 24 in his supply!

Step-by-step explanation:

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Kevin, Michael and Darren all do their own laundry at home. Kevin does his laundry every 9 days, Michael every 10 days, and Darr
VladimirAG [237]

Answer:

In 180 days the three of them will do their laundry again on the same day.

Step-by-step explanation:

we need to find the least common factor or 9, 10 and 12:

LCM(9, 10, 12) = 180

5 0
3 years ago
Read 2 more answers
Problem 10-01 NPV A project has an initial cost of $66,950, expected net cash inflows of $14,000 per year for 9 years, and a cos
svlad2 [7]

Answer:

NPV = $13,676.33

Step-by-step explanation:

First, find the present value of the cash inflows. You can solve this question using a Financial calculator;

14,000 per year is a recurring cashflow hence the PMT

PMT = 14,000

I/Y = 10%

N= 9

FV =0

then CPT PV = 80,626.33

NPV = -Initial investment + PV of future cash inflows

NPV = -66,950 + 80,626.33

NPV = $13,676.33

"NPV" button, then , then "CPT".

The answer to the NPV = $13,676.33

5 0
3 years ago
Integrate the following. ∫<img src="https://tex.z-dn.net/?f=5x%5E%7B4%7D%20dx" id="TexFormula1" title="5x^{4} dx" alt="5x^{4} dx
Vadim26 [7]

Answer:

\displaystyle D)  {x}^{5}  +  \rm C

Step-by-step explanation:

we would like to integrate the following Integral:

\displaystyle \int 5 {x}^{4} \, dx

well, to get the constant we can consider the following Integration rule:

\displaystyle \int c{x} ^{n}  \, dx  =  c\int  {x}^{n}  \, dx

therefore,

\displaystyle 5\int  {x}^{4} \, dx

recall exponent integration rule:

\displaystyle \int {x} ^{n}  \, dx  =  \frac{ {x}^{n + 1} }{n + 1}

so let,

  • n = 4

Thus integrate:

\displaystyle  =  5\left( \frac{ {x}^{4+ 1} }{4 +  1}  \right)

simplify addition:

\displaystyle  =  5\left( \frac{ {x}^{5} }{5}  \right)

reduce fraction:

\displaystyle  =  {x}^{5}

finally we of course have to add the constant of integration:

\displaystyle  \boxed{ {x}^{5}  +  \rm C}

hence,

our answer is D)

7 0
3 years ago
Read 2 more answers
Solve the following quadratics. State the FACTORS AND SOLUTIONS. 1. 2x^2 - 7x + 3 2. 3x^2 + 7x +2
tekilochka [14]

Answer:

1. x = 3, 1/2 (solutions); (x - 3)(2x - 1) (factors)

2. x = -1/3, -2 (solutions); (3x + 1)(x + 2) (factors)

Step-by-step explanation:

<u>1. 2x^2 - 7x + 3</u>

To solve problem 1, you will need to identify your a, b, and c values in this quadratic function.

Since this problem is in standard form, it will be easy to identify these values. The standard form of a quadratic function is ax^2 + bx + c.

The a value is 2, the b value is -7, and the c value is 3 if we use our standard form and see which numbers are plugged into it.

Since we know that

  • a = 2
  • b = -7
  • c = 3

we can use the quadratic formula: x = \frac{-b~\pm~\sqrt{b^2~-~4ac} }{2a}

Substitute the a, b, and c values into the quadratic formula: x=\frac{-(-7)\pm\sqrt{(-7)^2-4(2)(3)} }{2(2)}

Now simplify using the laws of pemdas: x=\frac{7\pm\sqrt{(49)-(24)} }{4}

Simplify even further: x=\frac{7\pm\sqrt{(25)} }{4} \rightarrow x=\frac{7\pm (5) }{4}

Now split this equation into two equations to solve for x: x=\frac{12 }{4} ~~and~~ x=\frac{2 }{4}

12/4 can be simplified to 3, and 2/4 can be simplified to 1/2.

This means your solutions to problem 1 is 3, 1/2.

\boxed {x=3,\frac{1}{2} }

There is also another way to solve for the quadratic functions, and this was by factoring.

If you factor 2x^2 - 7x + 3 using the bottoms-up method, you will get (x - 3)(2x - 1).

After factoring, solving for the solutions is simple because all you have to do is set each factor to 0.

  • x - 3 = 0
  • 2x - 1 = 0

After solving for x by adding 3 to both sides, or by adding 1 to both sides then dividing by 2, you will end up with the same solutions: x = 3 and x = 1/2.

<u>2. 3x^2 + 7x + 2</u>

To save time I'll be using the bottoms-up factoring method, but remember to refer back to problem 1 (quadratic formula) if you prefer that method.

Factor this quadratic function using the bottoms-up method. After factoring you will have (3x + 1)(x + 2). These are your factors.

Now to solve for x and find the solutions of the quadratic function, you will set both factors equal to 0.

  • 3x + 1 = 0
  • x + 2 = 0

Solve.

<u>First factor:</u> 3x + 1 = 0

Subtract 1 from both sides.

3x = -1

Divide both sides by 3.

x = -1/3

<u>Second factor:</u> x + 2 = 0

Subtract 2 from both sides.

x = -2

Your solutions are x = -1/3 and x = -2.

\boxed {x = -\frac{1}{3} , -2}

7 0
3 years ago
Complementary angles definition geometry
sesenic [268]
Two angles that added together equal 90 degrees
6 0
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