First step is to find what should be the required total of sum of Score after fourth test, to identify how much more or less she need to score in his fourth test.
Since Mean = (Sum of Scores)/number of test
using above formula we determine what is the required sum of score.
82 = (Sum of Scores)/4
⇒ 82 × 4 = 328
So in four test she should have score total as 328
So Score require in fourth test = Required Score Total - (total score in 3 tests)
= 328 - ( 72 + 97 + 82 ) = 77
So she need score of 77 to be at mean of 82 after fourth test and get qualify for the team
Answer:
(3, 9)
Step-by-step explanation:
Set 3x and 2x+3 equal to each other forming an equation in x.
3x=2x+3
Solve for x.
x=3
Substitute the given value of x into the equation y=3x.
y=3x3
Solve for y.
y=9
(x, y) = (3, 9)
Hope this helps :)
Answer: 1/20
To find P(Q and R), you have to multiply P(Q) by P(R) to get the probability that both events will occur. P(Q) = 1/8, and P(R) = 2/5, so when multiplied together, you get 2/40. This simplifies to 1/20, meaning P(Q and R) = 1/20.
This is vague. Any dimensions that make a triangle can make more than one, just draw another right next to it. What's really being asked is which dimensions can make more than one non-congruent triangle.
<span>A. Three angles measuring 75°,45°, and 60°.
That's three angles, and 75+45+60 = 180, so it's a legit triangle. The angles don't determine the sides, so we have whole family of similar triangles with these dimensions. TRUE
<span>B. 3 sides measuring 7, 10, 12?
</span>Three sides determine the triangles size and shape uniquely; FALSE
<em>C. Three angles measuring 40</em></span><span><em>°</em></span><em>, 50°</em><span><em>, and 60°? </em>
40+50+60=150, no such triangle exists. FALSE
<em>D. 3 sides measuring 3,4,and 5</em>
Again, three sides uniquely determine a triangle's size and shape; FALSE
</span>
Answer:
V= about 4,222.3 units
Step-by-step explanation:
d=24 so r=12 d/2=r
V= pi r sq times h/3
V=pi 12 sq times 28/3
V= pi 144 (28/3)
V= about 4,222.3
