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3 years ago

Sino gusto pointspointspoints!!!!

Biology

1 answer:

sashaice [31]3 years ago

3 0

Answer:

Gusto ko ng mga purong iyon

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Marsupials are found in north america and australia, but they would not have been able to swim across the ocean. according to sc

Shtirlitz [24]

Marsupials used to have adaptations that allowed them to swim but lost these adaptations over time.

<h3>What is Adaptation?</h3>

The term adaptation has to do with those changes that allow an organism to effectively survive and reproduce in its habitat. They could by physiological or morphological changes.

The reason why the Marsupials are found in North america and australia is that, Marsupials used to have adaptations that allowed them to swim but lost these adaptations over time.

Learn more about adaptations: brainly.com/question/1686177

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2 years ago

One reason tundra plants are small and grow close to the ground is that

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Tundra ecosystem is cold and sunlight is short. Plants need sunglight and warmth in order to grow, thus plants in tundra are shorter and cloers to the ground since the ground is warmer than the air

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4 years ago

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Petroleum and natural gas form from _____.

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They form natural gas or fuel and coal.

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4 years ago

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True or false: in a chemical reaction matter cannot be created or destroyed.

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Pretty sure its truth / no edit here

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3 years ago

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A new microorganism is isolated from a lake and is placed into a solution of KCl. The voltage difference across its membrane is

Leona [35]

Answer: $\Delta U=$ 1.922x10⁻²⁰ Joules

Explanation: Electric Potential Energy (U) is the energy a charged object has due to its location in an electric field and it will only exist with the object is charged.

Voltage or Electric Potential Difference (V) is external work done to move a charge from one point to another in a electric field.

These terms have a relationship, which is given by:

$\Delta U=q\Delta V$

where

q is the charge

Proton is positive and has a charge of 1.6x10⁻¹⁹C.

Unit for potential energy is Joule (J). The relation between mV and J is

1mV = 10⁻³J

Then:

V = 120x10⁻³

V = 0.12

So, for a proton to move from the negative side of a membrane to the positive:

$\Delta U=q\Delta V$

$\Delta U=1.6.10^{-19}.0.12$

$\Delta U$ = 1.922 x 10⁻²⁰

Energy necessary to transport a proton from negative side of the membrane to the positive is 1.922 x 10⁻²⁰J.

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3 years ago

Sino gusto pointspointspoints!!!!​

Sino gusto pointspointspoints!!!!