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Bumek [7]
3 years ago
14

Write 342 to 1 significant figure​

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0

Answer:

300

Step-by-step explanation:

A significant figure is the most important (largest) number you can round it to.

As it wants 1 significant figure, you count 1 to the left and round the 4 down.

Hope this helps :)

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PLEASE HELP I HAVE NO IDEA WHAT IM DOING!!!
algol13

Answer: 28.26


Step-by-step explanation:

What your looking for is called the annulus (or the difference of two concentric circles). You can find the annulus by subtracting the area of the inner circle from the area of the outer circle. Volume of a circle= πr²

You are given the diameter in these problems, so you need radius.

For the first circle (8 in one) :

8/2=4    r=4

A=3.14(4)²

A=50.24

For the second one (10 in one) :

10/2=5   r=5

A=3.14(5)²

A=78.5

To find the measure of the annulus, you subtract those numbers, getting 28.26


8 0
4 years ago
A rock with mass of 5.0 kg is carried up a small hill 10 meters high. What is the potential energy of the rock at the hilltop?
Sonja [21]

490J

Step-by-step explanation:

Given parameters:

Mass of rock = 5kg

Height of hill = 10m

Unknown:

Potential energy at the hilltop = ?

Solution:

Potential energy is the energy at rest of a body. it is given as:

                P.E = mgh

m is the mass of the body

g is the acceleration due to gravity = 9.8m/s²

h is the height of the hilltop

     P.E = 5 x 10 x 9.8 = 490J

Learn more:

Potential energy brainly.com/question/10770261

#learnwithBrainly

5 0
3 years ago
What's the slope of y=x+5
disa [49]

Step-by-step explanation:

Hey there!

Given;

The equation is; y = X+5.

Comparing the equation with y = mx+c. Where "m" represents the slope, "c" is y-intercept and y is a variable. We get;

Slope (m)= 1

<em><u>Hop</u></em><em><u>e</u></em><em><u> it</u></em><em><u> </u></em><em><u>he</u></em><em><u>lps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
3 years ago
Read 2 more answers
La densidad de un líquido es de 1.5 gr/cm3 su masa es de 7 libras Determina la cantidad de litros que ocupan dichos líquidos
egoroff_w [7]

Answer:

<em>La cantidad de litros que ocupa dicho líquido es:</em>

  • <u>2,12 Litros</u>

Step-by-step explanation:

<em>El volumen de un líquido puede obtenerse al tener tanto su densidad como su masa usando la siguiente fórmula:</em>

  • <em>Densidad = masa / volumen</em>

<em>Al despejar volumen se obtiene:</em>

  • <em>Volumen = masa / densidad </em>

<em>Por lo cual, si se reemplazara la fórmula quedaría:</em>

  • <em>Volumen = 7 Lb / 1.5 gr/cm^3</em>

<em>Sin embargo, </em><u><em>para operar, las unidades en las que se expresa la masa deben coincidir con las unidades de la densidad</em></u><em>, por lo cual vamos a convertir las libras en gramos teniendo en cuenta el siguiente factor de conversión:</em>

<em>1 libra = 453,592 gramos</em>

<em>Entonces:</em>

<em>7 lb =  453,592 gr * 7 = 3175,144 gr</em>

<em>Ahora este valor reemplaza la masa en la fórmula y calculamos:</em>

  • <em>Volumen del líquido =  3175,144 gr / 1.5 gr/cm^3</em>
  • <u><em>Volumen del líquido = 2116,762667 cm^3</em></u><em> (He utilizado todos los decimales para obtener el resultado exacto).</em>

<em>A simple vista ya se tiene el volumen del líquido en cuestión, sin embargo, el ejercicio pide que sea expresado en litros, por lo cual vamos a convertir los centímetros cúbicos en litros teniendo en cuenta el siguiente factor de conversión:</em>

<em>1 litro = 1000 centímetros cúbicos.</em>

<em>Ahora podemos aplicar una regla de tres simple, si:</em>

  • <em>1000 cm^3 = 1 L</em>
  • <em>2116,762667 cm^3 = x</em>

<em>Y operamos:</em>

  • <em>x = (2116,762667 cm^3 * 1 L) / 1000 cm^3</em>
  • <u><em>x = 2,116762667 L</em></u>

<em>O si quieres un valor aproximado:</em>

  • <u><em>x = 2,12 Litros.</em></u>

<em>Entonces, la cantidad de litros teniendo en cuenta la densidad y la masa brindadas es </em><u><em>2,12 litros</em></u><em>.</em>

8 0
3 years ago
To multiply fractions do you need a common denominator
Kisachek [45]
No.
you need a common denominator when you ADD fractions, but not when you multiply.
5 0
3 years ago
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