Answer:
length = 115 cm
width = 108 cm
Step-by-step explanation:
The perimeter of a rectangular swimming pool is 446 centimeters
LEt L be the length of the pool
The width of the pool is 7 centimeters less than the length of the pool.
width = length - 7
W= L-7
Given perimeter = 446
Perimeter of rectangle = 2(length)+2(width)
446 = 2(L) + 2(W) we know W = L-7
446 = 2(L) + 2(L-7)
446 = 2L + 2L - 14
Add 14 on both sides
460 = 4L
divide by 4 on both sides
L= 115
Length L= 115
Width W = L - 7 = 115 - 7= 108
Answer: d
Step-by-step explanation:
t= b1- B0/ SE(b1) = 2.37-0/0.65= 3.646 -> 3.65
1st hen =6x
2nd hen =7y
1st hen is greater than 2nd
so you get 6x > 7y
Answer:
At first, we divide the parallelogram into two triangles by joining any two opposite vertices. These two triangles are exactly the same (congruent) and thus have equal areas. The area of the parallelogram is the summation of the individual areas of the two triangles. We drop a perpendicular from a vertex to its opposite side to get an expression for the height of the triangles. The area of the individual triangle is 12×base×height12×base×height .The area of the parallelogram being twice the area of the triangle, thus becomes after evaluation base×heightbase×height .
Complete step by step answer:
The parallelogram can be divided into two triangles by constructing a diagonal by joining any two opposite vertices.


In the above figure, ΔABDΔABD and ΔBCDΔBCDare the two such triangles. These two triangles have:
AB=CDAB=CD (as opposite sides of a parallelogram are equal)
AD=BCAD=BC (opposite sides of a parallelogram are equal)
BDBD is common
Thus, the two triangles are congruent to each other by SSS axiom of congruence. Since, the areas of two congruent triangles are equal,
⇒area(ΔABD)=area(ΔBCD)⇒area(ΔABD)=area(ΔBCD)
Now, we need to find the area of ΔABDΔABD . We draw a perpendicular from DD to the side ABAB and name it as DEDE . Thus, ΔABDΔABD is now a triangle with base ABAB and height DEDE .
Then, the area of the ΔABD
Answer:
do this ok this is step by step answer
